Segment registers-microprocessor, Assembly Language

Assignment Help:

Segment Registers

The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thuseach segment has 64 Kbytes of memory. There are 4 segment registers, viz, Data Segment Register (DS), Code Segment Register (CS), and Segment Register (SS). AndExtra Segment Register (ES) Stack The code segment register is utilized for addressing a memory location in the code segment of the memory, where the executable program is stored. As similar, the data segment register points to the data segment of the memory, where the data is resided. The additional segment also refers to a segment which really is another data segment of the memory. Thus the additional segment also contains data. The stack segment register is utilized for addressing stack segment of memory. The stack segment is that type segment of memory which is utilized to store stack data. The CPU utilizes the stack for provisionally storing important data, for example the contents of the CPU register which will be needed at a later stage. The stack grows down, for example. the data is pushed onto the stack in the memory locations with decreasing addresses.  When this information will be needed by the CPU, they will be popped off from the stack. When addressing of any location in the memory bank, the physical address is computed from 2 parts, the first is segment address and the second offset.  The segment registers contain 16-bit segment base addresses, related to different type of segments. Any of the pointers,BX andindex registers can contain the offset of the location to be addressed. The benefit of this scheme is that in place of maintaining a 20-bit register for a physical address, the processor only maintains two 16-bit registers which are within the word length capacity of the machine. Thus the DS, CS, SS and ES segment registers respectively contain the segment addresses for thedata, code, stack and extra segments of memory. It can be noted that all these segments are the logical segments. They can or cannot be physically separated. In other terms, a single segment may require more than one memory chip or more than 1 segment may be accommodated in a single memory chip.

 


Related Discussions:- Segment registers-microprocessor

Code for reading flow & generating led output, Code for Reading Flow & Gene...

Code for Reading Flow & Generating LED Output The code starts with the scanning of the PORT 3, for reading the flow status to check for various flow conditions and compare to

Can you write this Program for me please? , $NOMOD51 $NOSYMBOLS ;**********...

$NOMOD51 $NOSYMBOLS ;***************************************************************************** ; Spring 2013 Project ; ; FILE NAME : Project.ASM ; DATE : 3/30/20

Read file in 8086, Write a procedure to read a text file and copy its cont...

Write a procedure to read a text file and copy its contents to another text file using 8086 assembly language .

Computer organization, write a program using assembly language that print y...

write a program using assembly language that print your name

How to write an assembly program-microprocessor, How to write an assembly p...

How to write an assembly program The initial step in writing an assembly language program is to identify and study the problem. After studying the problem, choose the logical m

Software interrupts-microprocessor, Software Interrupts Software interr...

Software Interrupts Software interrupts are the result of an INT instruction in an executed program.  It may be assumed as a programmer triggered event that immediately stops e

Programming, Using the following table as a guide, write a program that ask...

Using the following table as a guide, write a program that asks the user to enter an integer test score between 0 and 100. The program should display the appropriate letter grade.

Program for declare the threshold, 1. Start your program at address $8500. ...

1. Start your program at address $8500. To do this you need to inform the assembler, through the EQU and ORG assembler directives, that you want your program to start at $8500. Thi

Convert from C to 8086 assembly language, Trying to convert small programs ...

Trying to convert small programs from C to 8086 assembly language using emu 8086 emulator. I converted to low level C, but struggling with converting to the Assembly language.

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd