Segment registers-microprocessor, Assembly Language

Assignment Help:

Segment Registers

The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thuseach segment has 64 Kbytes of memory. There are 4 segment registers, viz, Data Segment Register (DS), Code Segment Register (CS), and Segment Register (SS). AndExtra Segment Register (ES) Stack The code segment register is utilized for addressing a memory location in the code segment of the memory, where the executable program is stored. As similar, the data segment register points to the data segment of the memory, where the data is resided. The additional segment also refers to a segment which really is another data segment of the memory. Thus the additional segment also contains data. The stack segment register is utilized for addressing stack segment of memory. The stack segment is that type segment of memory which is utilized to store stack data. The CPU utilizes the stack for provisionally storing important data, for example the contents of the CPU register which will be needed at a later stage. The stack grows down, for example. the data is pushed onto the stack in the memory locations with decreasing addresses.  When this information will be needed by the CPU, they will be popped off from the stack. When addressing of any location in the memory bank, the physical address is computed from 2 parts, the first is segment address and the second offset.  The segment registers contain 16-bit segment base addresses, related to different type of segments. Any of the pointers,BX andindex registers can contain the offset of the location to be addressed. The benefit of this scheme is that in place of maintaining a 20-bit register for a physical address, the processor only maintains two 16-bit registers which are within the word length capacity of the machine. Thus the DS, CS, SS and ES segment registers respectively contain the segment addresses for thedata, code, stack and extra segments of memory. It can be noted that all these segments are the logical segments. They can or cannot be physically separated. In other terms, a single segment may require more than one memory chip or more than 1 segment may be accommodated in a single memory chip.

 


Related Discussions:- Segment registers-microprocessor

Program to accept the input from user, Write an assembly language program t...

Write an assembly language program that will: accept keyboard input of a positive integer value N; compute the sum S= 1+ 2 + 3 + ... + N; print (output) the computed su

Computes the integral square root - assembly program, Computes the integral...

Computes the integral square root: Problem: Square Root:   For this problem you will write a short assembly program that computes the integral square root of an input numb

Execution unit and bus interface unit-microprocessor, Execution Unit (EU) a...

Execution Unit (EU) and Bus Interface Unit (BIU) : 8086 consist of two processors called EU and BIU. Two Processors can work parallel. This improves speed of execution. BIU fi

8251 programmable/communication interface-microprocessor, 8251 Programmable...

8251 Programmable/Communication Interface As an instance of a serial interface device let us suppose Intel's 8251 A programmable communication interfaces. The 8251A is diagram

Mmm development board, Write an account of your findings and produce a repo...

Write an account of your findings and produce a report containing all aspects of the above. Include a step-by-step 'simple User Guide' so that your program can be operated as inten

Memory segmentation-microprocessor, Memory Segmentation : The  memory ...

Memory Segmentation : The  memory in an 8086/8088  based system is organized as segmented memory. In this scheme, the whole physically available memory can be divided into a n

Code, 1. Assembly code for the flow chart we did in the class about the sim...

1. Assembly code for the flow chart we did in the class about the simple I/O interface driver 2. Enhanced driver (flow chart and its assembly code) to cater for interruptions in th

Rcr-rcl-logic instruction-microprocessor, RCR: Rotate Right through Carry:...

RCR: Rotate Right through Carry:- This instruction rotates the contents  bit-wise of the destination operand right by the specified count through carry flag (CF). For each operati

Cmp-arithmetic instruction-microprocessor, CMP: Compare: - This instructio...

CMP: Compare: - This instruction compares the source operand, which can be a register or memory location an immediate data with a destination operand that might be a register or a

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd