Seasonal-component analysis, Mechanical Engineering

Assignment Help:

Seasonal-Component Analysis:

A food processor uses a moving average to forecast next month's demand. Actual demand data for the past few months is available as depicted in the following table.

 

618_Seasonal-Component Analysis.png

 (a) Calculate a simple five-month moving average to forecast demand for month 22.

 (b) Calculate a weighted three month moving average where the weights are highest for the latest month and descend in order of 3, 2, 1.

Solution

 (a) While only one 5-month moving average is needed, it is taken as the average of the demand for the last 5 months for which the data is available.

So, MA = (117 + 108 + 110 + 101 + 94) /5 = 106 units

Therefore forecast for the 22nd month = 106 units

This value of MA is a deseasonalised monthly demand. While the actual demand for 22nd month becomes known, a new moving average is computed by dropping the oldest monthly demand (that means of 17th month) and including the most recent one of 22nd month.

 (b) MAweight = ∑ (weight) (X ) /∑ (weight)

Weight            Value   Total

3          ×          117      =          351

2          ×          108      =          216

1          ×          110      =          110

----------------------------------------

                                              677

∴ MAweight = 677/6 ≅ 113 units.

Let us take another instance. The actual demand for trailors for the months of year 2000 are shown in Table. The moving average may be calculated by averaging the first n items of data into a single number (where n is the number of items of data to be averaged). The grouping is then incremented by one data-item. The three-month moving average for third to the last month is shown in the third column, while forecasts for the fourth month and subsequent months are depicted in 4th column. The difference of actual demand and forecast demand is shown in the last column.

For selecting the value of n, it must be kept in mind that the larger the value of n, the greater the dampening or smoothing effect. A large n shall show the entire trend but can obliterate seasonal cycles. Alternatively, smaller n has very little smoothing effect and the moving average tends to resemble the original data.

Table: Three Months Moving Averages

568_Seasonal-Component Analysis1.png

The ratio of actual demand in a given period to the moving average demand for the same period is known as the specific seasonal index. Its value determines the seasonal effect and some random influences of the period for which it is calculated. By averaging the values of the specific seasonal index for the same period in successive years the remaining random influence may be smoothened out, and thus seasonal effects can be isolated.


Related Discussions:- Seasonal-component analysis

Thin cells, what type of stresses a thin cell is subjected to?

what type of stresses a thin cell is subjected to?

Optimization, what are the different method for worm gear optimization

what are the different method for worm gear optimization

Illustrate process of radiographic examination, Q. Illustrate process of Ra...

Q. Illustrate process of Radiographic Examination? Radiographic examination of welded joints shall be performed when required by the Code or additionally when specified in this

Find out the thickness of the metal and the hoop stress, Find out the thick...

Find out the thickness of the metal and the hoop stress: The cylinder of a hydraulic press has an internal diameter of 0.3 m & is to be designed to withstand a pressure of 10

Fatigue crack propagation, Fatigue crack propagation: If it is assumed...

Fatigue crack propagation: If it is assumed that no plastic deformation occurs around crack tip and law of fatigue crack propagation for place of above Example is da/dN =  10

Calculate the safe load using eulers formula, A 1.5m long column has circul...

A 1.5m long column has circular cross-section of 5cm diameter. One of the end of the column is fixed in the position and direction and other end is free. Taking factor of safety as

Rigid joints, Solve the support reactions at A and D by using the force met...

Solve the support reactions at A and D by using the force method. A is a fixed support; B and C are rigid joints; and D is a pin support. EI is constant for all members.

Find the coefficient of friction between ladder and floor, Find the coeffic...

Find the coefficient of friction between ladder and floor: A ladder of 5m long rests on horizontal ground and leans against smooth vertical wall at an angle of 70° with the h

Introduction to basic troubleshooting of motorcycle , INTRODUCTION: Previo...

INTRODUCTION: Previously, you studied about the repairing some parts of a motorcycle. In this unit, we shall mainly emphasise on the troubleshooting of the basic problems. This un

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd