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1. A screw gauge consists of U- shaped metallic frame F. To one end of this frame, a flat shaft is fixed. On the opposite end of a hollow long cylinder C is fixed.2. The hollow cylinder has fine threads cut inside it and it serves as the nut.On the outer surface of this hollow cylinder, a line parallel to its axis, called index line is drawn and is divided into some equal divisions (1 mm or 0.5 mm). This serves as the pitch scale (P).3. A screw with a flat tip (shaft) having threads exactly identical to the threads cut inside the cylinder, moves through the cylinder C. To the other end of the screw, a milled head M is connected.4. To this milled head one end of a barrel B (another hollow cylinder) is connected. This Barrel B forms a jacket to the first hollow cylinder C.5. The other end of the barrel is tapered and has 100 or 50 equal divisions on it. This is called the head scale (H).6. When the two flat shafts exactly opposite to each other , are in contact, the distance between them is zero. In this position, the edge of the head scale must coincide with the zeroth division of the pitch scale.Further, the index line will be coinciding with the zero of the head scale
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derivations on above topic?
I want to measure H, not B The magnets in question are permanent magnets (large Neo or SmCo magnets), not coils =====================....Steel ____........................____ |.
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