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SBB: Subtract with Borrow :- The subtract with borrow instruction subtracts the source operand and the borrow flag (CF) which might reflect the result of the past calculations, from the destination operand. Subtraction along with the borrow, here means subtracting value 1 from the subtraction obtained by SUB, if carry (borrow) flag is the set.
The result is stored in the destination operand. All the flags are affected (Condition code) by this instruction. The instance of this instruction is following:
Example :
1. SBB O100H Immediate [destination AX]
2. SBB AX.BX Register
3. SBB AX, [5000H] Direct
4. SBB [5000H], 0100 Immediate
Instruction set of 8086 : The 8086/8088 instructions are categorized into the following major types. This section describes the function of each of the instructions with approp
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use">http://www.raritanval.edu/uploadedFiles/faculty/cs/full-time/Brower/CISY256/2013Spring/CISY256%20Assembly%20Project.pdf use microsoft visual 2010 and http://www.asmirvine.c
NOT : Logical Invert: The NOT instruction complements (inverts) the contents of an a memory location or operand register bit by bit. The instance are as following: Example :
Write a MIPS/SPIM assembly language program that prints the smallest and largest values found in a non-empty table of N word-sized integers. The address of the first entry in your
INT N : Interrupt Type N:- In the interrupt structure of 8086/8088, 256 interrupts are distinct equivalent to the types from OOH to FFH. When an instruction INT N is executed,
Programming with an assembler The procedure of hand-coding 8086 programs is somewhat tiresome; hence generally a programmer may find it hard to get a correct listing of the mac
DEC: Decrement :- The decrement instruction subtracts 1 from the contents of the particular memory location or register. All the conditions code flags except carry flag are affec
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