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SBB: Subtract with Borrow :- The subtract with borrow instruction subtracts the source operand and the borrow flag (CF) which might reflect the result of the past calculations, from the destination operand. Subtraction along with the borrow, here means subtracting value 1 from the subtraction obtained by SUB, if carry (borrow) flag is the set.
The result is stored in the destination operand. All the flags are affected (Condition code) by this instruction. The instance of this instruction is following:
Example :
1. SBB O100H Immediate [destination AX]
2. SBB AX.BX Register
3. SBB AX, [5000H] Direct
4. SBB [5000H], 0100 Immediate
) What is the difference between re-locatable program and re-locatable data?
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A good starting point for your program is the toupper.asm program shown in class. It already queries the user for input and sets up a loop that looks at each character of the input
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Pin diagram of 8088 : The pin diagram of 8088 is shown in given figure. Most of the 8088 pins and their functions are exactly similar to the corresponding pins of 8086. Hence
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