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An α particle is a positively charged particle.Rutherford observed the behaviour of these particles when they approach the interior of the atoms as shown in fig.
Rutherford observed that most of the α particles like a, a1 , pass through the atom un deflected.
Some of the particles like b, b1 get scattered by the atom at smaller angles of deflections. The particles like c, c1 undergo large deflection at an angle less than 180o but more than 90o . The particles like ‘d' get deflected such that they are sent back as d1 with an angle of 180o.Such large - angle deflections require strong forces to be acting on the α particles. Rutherford argued that this would be possible if all the positive charges and mass of the atom was concentratedin a very small central region which he called the nucleus of the atom. Then the large angle deflections of α particles are c, c1, due to electric repulsive forces caused by the nucleus. From the data obtained in this experiment Rutherford calculated the radius of the nucleus and found it to be shorter than 2.4×10-15m. Because the mass of the electron is only about 1/7000th mass of an alpha particle, the effect of the presence of electrons inside the atom on the deflection of the alpha particles can safely be ignored.
When a moving body changes with time,then we say that the body has acceleration.simentaniously the change in velocity is equal then it is called uniform acceleration .
WHERE DOES C.O.G AND C.O.M DIFFER?....GENERALLY BOTH COINCIDES....GIVE EXAMPLE WHERE BOTH DIFFER? Ans) C.O.G and C.O.M mainly coincides at the see-level region.But C.O.G is a va
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A mild steel ring has a radius of 50mm and a cross-sectional area of 400mm 2 . A current of 0.5 A flows in a coil wound uniformly around the ring and the flux formed is 0.1mWb
Q. An aircraft having awing span of 20.48 m flies at a speed of 40 ms -1 . If the vertical component of the earth's magnetic field is 2 X 10 -5 T, compute the emf induced between
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uncontrollable reaction
Two elements A and B form compounds having molecular formulae AB 2 and AB 4 . dissolved in 2O g of benzene, 1 g of AB2 lower the freezing point by 2.3 K, whereas 1 g of AB4 lowers
The work done by a friction force is: a) Always positive b) Always negative c) Always zero d) Either positive or negative depending upon the situation. An
Time Base Control 2 Shows the effect of modifying the time base control on the show while there is an input voltage varying in time.
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