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null(nil) = true // nil refer for empty tree
null(fork(e, T, T'))= false // e : element , T and T are two sub tree leaf(fork(e, nil, nil)) = true
leaf(fork(e, T, T')) = false if not null(T) or not null(T')
leaf(nil) = error
left(fork(e, T, T')) = T
left(nil) = error
right(fork(e, T, T')) = T' right(nil) = error
Contents (fork (e, T, T')) = e contents (nil) = error
Consider the definition of Tree (ADT). A way to think of a binary tree is that this is either empty (nil) or have an element and two sub trees that are themselves binary trees. Fork operation joins two sub trees along a parent node and generates another Binary tree. It might be noted that a tree containing a single leaf is described to be of height 1.
Definition: A tree is connected, acyclic graph
Q. What do you mean by the best case complexity of quick sort and outline why it is so. How would its worst case behaviour arise?
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