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f(x)=5x2=5x-2 f(3)
5x+2x-17=53
how many does a rhombus have
|3-x\2|-3>2 less then equal to
Can you help me explain this topic please?
Properties of f( x ) = b x 1. The graph of f( x ) will always have the point (0,1). Or put another way, f(0) = 1 in spite of of the value of b. 2. For every possible b b x
5p-6/7p^8
-6k+7k=
Using synthetic division do following divisions. Divide 2x 3 - 3x - 5 by x + 2 Solution Okay in this case we have to be a little careful here. We have to divide by a
I am trying to figure out this answer f(x) = -3/4x + 4. but think I am getting it all wrong
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