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Q. Take an array A[20, 10] of your own. Suppose 4 words per memory cell and the base address of array A is 100. Find the address of A[11, 5] supposed row major storage.
Ans.
A[20, 10]
W = 4 words
Base (A) = 100
A [11, 5] → in row major m x n
loc [ a [i] [j] = base (a) + w [n [i - lbr] + ( j - lbc)]
= 100 + 4 [10 (11) + 5]
= 100 + 4[110+5]
=100 + 115 *4
= 560
bst for 40,60,25,50,30,70,35,10,55,65,12
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