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ROR : Rotate Right without Carry: This instruction rotates the contents of destination operand to the bit-wise right either by one or by the count specified in register CL, excluding carry. The least significant bit is pushed into the carry flag and concurrently it is transferred into the most significant bit position at each operation. Remaining bits are shifted right by the particular positions. The SF, PF, and ZF flags are remain unchanged by the rotate operation. The operand might be a memory location or register but it can't be an immediate operand. Given figure described the operation. The destination operand might be a memory location or a register (except a segment register).
Figure : Execution of ROR Instruction
(1) Write a program that will: (a) display "Enter Your Name:" (b) convert the entered name to Capital letters (if small), If any other character is entered, the program wil
use">http://www.raritanval.edu/uploadedFiles/faculty/cs/full-time/Brower/CISY256/2013Spring/CISY256%20Assembly%20Project.pdf use microsoft visual 2010 and http://www.asmirvine.c
Problems: 1. Write a single program. Each of the problems (2-4) should be written within a procedure. Your “main” procedure should call each procedure. Before calling each proc
You have to write a subroutine (assembly language code using NASM) for the following equation.
LODS : Load String Byte or String Word:- The LODS instruction loads AL/AX register by the content of a string pointed to by DS:SI register pair. The SI is automatically modifie
Arithmetic Instruction : These instructions are usually perform the arithmetic operations, like subtraction ,multiplication, addition, and division along with th
) What is the difference between re-locatable program and re-locatable data?
write shell to calculate basic salary from given .
Write an application that does the following: (1) fill an array with 50 random integers; (2) loop through the array, displaying each value, and count the number of negative values;
Write an assembly language program to find the maximum of: y = x 6 - 14x 2 + 56x for the range -2 ≤ x ≤ 4, by stepping one by one through the range. The program should in
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