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Rolle's Theorem
Assume f(x) is a function which satisfies all of the following.
1. f(x) is continuous in the closed interval [a,b].
2. f(x) is differentiable in the open interval (a,b).
3. f(a) = f(b)
So, there is a number c as a < c < b and f′(c) = 0. Or, though f(x) has a critical point in (a,b).
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Rationalize the denominator for following. Suppose that x is positive. Solution We'll have to start this one off along with first using the third property of radica
Hi,Is this free?
L.H.S. =cos 12+cos 60+cos 84 =cos 12+(cos 84+cos 60) =cos 12+2.cos 72 . cos 12 =(1+2sin 18)cos 12 =(1+2.(√5 -1)/4)cos 12 =(1+.(√5 -1)/2)cos 12 =(√5 +1)/2.cos 12 R.H.S =c
It's easier to describe an explicit solution, in this case and then tell you what an implicit solution is not, and after that provide you an illustration to demonstrate you the dif
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application of radious of curvatur
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