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At a distance of 4,000 ft from the launch site, a spectator is observing a rocket being launched. If the rocket lifts off vertically and is rising at a speed of 600 ft/sec when it is at an altitude of 3,000 ft, how fast is the distance between the rocket and the spectator changing at that instant?Solution) Distance=s=√(40002+h2), rate of change of distance=ds/dt=(ds/dh)(dh/dt)=(d(√(40002+h2)/dh)(dh/dt),dh/dt=600 ft/sec
I want to know about renewal time, such as the Greenland Ice shelf melting. How much does it cost to have the equations and to have this explained please?
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Presumptuous that it is understood that the object is in front of the mirror and anything on the other side of the mirror is behind the mirror is the following statement sufficient
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