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Risk DeterminationFor purpose of relative risk assessment, risk equals probability of vulnerability occurrence TIMES value MINUS percentage risk already controlled PLUS an element of uncertainty. For instance• Information asset A has a value score 50 and has 1 vulnerability: Vulnerability1 has a likelihood of 1.0 with no current controls and you estimate that the assumptions and data are 90 percent accurate.• Information asset B has a value score of 100 and has 2 vulnerability 2 has a likelihood of 0.5 with a current control which addresses 50 percent of risk. Vulnerability3 has a likelihood of 0.1 with no current controls.Resulting ranked list of risk ratings for the 3 vulnerabilities: Asset A: Vulnerability 1 rated as 55 = (50 x 1.0) –0% + 10% Where 55 = (50 x 1.0) – ( ( 50x 1.0)x0.0) + ( ( 50x1.0) x 0.1)55 = 50 - 0 + 5Asset B: Vulnerability 2 rated as 35 = (100 x 0.5) – 50% + 20% Where 35 = (100 x 0.5) – ( (100 x 0.5)x 0.5) + ( ( 100 x0.5) x 0.2)35 = 50 – 25 + 10Asset C: Vulnerability 3 rated as 12 = (100 x 0.1) – 0% + 20% Where 12= (100 x 0.1) – ((100 x 0.1) x 0.0) + ((100 x0.1) x 0.2)12 = 10 - 0 + 2
Problem (a) Differentiate between private key and public key encryption. (b) What issue with private key encryption is resolved with public key encryption? (c) Describe
every time i connect to WIFI the UC goes directly to 100% then i doesn''t want to come down. what shall i do ?
Designing and coding of Job search mechanism: Project Title: FREEHIVE (Sep 2005- Nov 2006) Role : Developer Domain : Social Network Client
For simplicity, each character is regarded as one data packet, which means that the data in each packet should have the max length of only 1 byte. Your own packet header (not th
FRAME FORMAT AND ERROR DETECTION The changed frame format also adds CRC. If there is an error happened in frame, then it typically causes receiver to removed frame. The frame
Problem (a) Below is a capture of an Ethernet II frame which contains an IPv4 packet and a TCP segment. The second screen capture is from the data portion of the frame.
IP DATAGRAM SIZE: Datagrams may have different sizes i.e. Header area is generally fixed (20 octets) but can have various options. Data area may contain between 1 octet and 6
QUESTION (a) What do you meant by data spoliation? (b) Justify the following statement: "Disk imaging differs from creating a standard backup of disk." (c) Why do yo
ARP RESPONSES Let's search out how does a computer know whether an incoming frame have an ARP message. The type field in the frame header defines that the frame contain an ARP
QUESTION (a) Describe the two possible configurations for 3DES (b) What is the main disadvantage of 3DES? (c) Why are most modern symmetric algorithm block ciphers? (d
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