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RISC architecture - computer architecture:
What is reduced regarding it? The answer of this question is that to make all instructions the equal length the number of bits that are used for the opcode is reduced. Accordingly fewer instructions are provided. The instructions that were thrown out are the less significant string and BCD (binary-coded decimal) operations. Acutely, now that memory access is limited there aren't various kinds of MOV instructions or ADD instructions. Therefore the previous architecture is called CISC (Complete Instruction Set Computer). RISC architectures are also known as LOAD/STORE architectures.
The number of registers in RISC is typically 32 or more. The first the MIPS 2000 and RISC CPU has 32 GPRs as different to 16 in the 68xxx architecture and 8 in the 80x86 architecture. The only disadvantage of RISC is the code size of it. Typically more instructions are required and there is a waste in short instructions (POP, PUSH).
For executing recursive function the data structure used is: For executing recursive function, stack is used as a data structure.
Home Shopping TV broadcast of goods for purchase, sent directly to a viewer . This online shopping is available because of e-commerce.
What is cache memory? The small and fast RAM units are known as caches. When the implementation of an instruction calls for data located in main memory, the data are obtained a
Explain Clone process. A clone process is generated using primitive type clone by duplicating its parent process. However unlike traditional processes it might be share its con
Q. Illustration of equivalent EXE program? An illustration of equivalent EXE program for COM program is: ; ABSTRACT this program adds 2 8-bit numbers in the memory locations
What are the various mechanisms for implementing I/O operations? a) Program controlled I/O b) Interrupts c) DMA
Q. Explain Random-access Semiconductor Memories Q. What is Basic memory cell? Explain Two Dimension Memory Organization with diagram.
Binary Resolution: However we saw unit resolution for a propositional inference rule in the previous lecture: (A? B, ¬B) /A Thus we can take this a little further to
state and prove distributive law?
Which of the memories stores the most number of bits ? Ans. most number of bits stores in 32M x 8 As 2 5 x 2 20 = 2 25 Therefore 1M = 2 20 = 1K x 1K = 2 10 x 2 10
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