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RISC architecture - computer architecture:
What is reduced regarding it? The answer of this question is that to make all instructions the equal length the number of bits that are used for the opcode is reduced. Accordingly fewer instructions are provided. The instructions that were thrown out are the less significant string and BCD (binary-coded decimal) operations. Acutely, now that memory access is limited there aren't various kinds of MOV instructions or ADD instructions. Therefore the previous architecture is called CISC (Complete Instruction Set Computer). RISC architectures are also known as LOAD/STORE architectures.
The number of registers in RISC is typically 32 or more. The first the MIPS 2000 and RISC CPU has 32 GPRs as different to 16 in the 68xxx architecture and 8 in the 80x86 architecture. The only disadvantage of RISC is the code size of it. Typically more instructions are required and there is a waste in short instructions (POP, PUSH).
Explain the different sub-functions of Process Scheduling. Process scheduling contains the subsequent sub-functions: 1. Scheduling: Chooses the process to be executed next
draw input and output charectoristics of BJT and justify CE configuration provides large current amplification
Q. What about division and multiply operations? In most of the older computers divisions and multiply were implemented using subtract/add and shift micro-operations. If a digit
How does one arrive at the probability of availability of free lines during the busy hour? One can arrive at the possibility of free lines throughout busy hour using the delay
Explain Top down parsing. Top down parsing: Specified an input string, top down parsing tries to derive a string identical to this by successive application of grammar rule
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Design a 32:1 multiplexer using two 16:1 multiplexers and a 2:1 multiplexer Ans. Design a 32 X 1 MUX by using two 16 X 1 MUX and one 2 X 1. Now here total 32 input lines
ALE-> Address latch enable...In the case of microcontroller (8051)& microprocessor 8085 the data line and low order 8 bit address lines are multiplexed. In order to getting address
Q. Explain Time Complexity in Parallel algorithms? As it takes place nearly everyone who implement algorithms wish to know how much of an individual resource (for example time
Write-through vs. write-back caches
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