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Q. How do we represent a max-heap sequentially? Explain by taking a valid example.
Ans: A max heap is also called as a descending heap, of size n is an almost complete binary tree of n nodes such as the content of each node is less than or equal to the content or matter of its father. If sequential representation of an almost whole binary tree is used, this condition reduces to the condition of inequality. Info[j] <= info[(j-1)/2] for 0 <= ((j-1)/2) < j <= n-1 It is very much clear from this definition that root of the tree contains the largest element in the heap in the descending heap. Any of the paths from the root to a leaf is an ordered list in the descending order.
Ans:
A max heap is also called as a descending heap, of size n is an almost complete binary tree of n nodes such as the content of each node is less than or equal to the content or matter of its father. If sequential representation of an almost whole binary tree is used, this condition reduces to the condition of inequality.
Info[j] <= info[(j-1)/2] for 0 <= ((j-1)/2) < j <= n-1
It is very much clear from this definition that root of the tree contains the largest element in the heap in the descending heap. Any of the paths from the root to a leaf is an ordered list in the descending order.
Example: (Single rotation into AVL tree, while a new node is inserted into the AVL tree (LL Rotation)) Figure: LL Rotation The rectangles marked A, B & C are trees
Using the cohen sutherland. Algorithm. Find the visible portion of the line P(40,80) Q(120,30) inside the window is defined as ABCD A(20,20),B(60,20),C(60,40)and D(20,40)
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1. Start 2. Get h 3. If h T=288.15+(h*-0.0065) 4. else if h T=216.65 5. else if h T=216.65+(h*0.001) 6. else if h T=228.65+(h*0.0028) 7. else if h T=270.65 8.
Q. Using the following given inorder and preorder traversal reconstruct a binary tree Inorder sequence is D, G, B, H, E, A, F, I, C
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A full binary tree with n leaves have:- 2n -1 nodes.
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