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Replace the two parallel forces by single force:
Replace the two parallel forces acting on the control lever by a single equivalent force R.
Sol.: Since single equivalent force is resultant.
Let ΣH and ΣV be the horizontal and vertical component of the resultant. Resolving all the forces in horizontal direction
ΣH = 50 - 80 = -30N ...(i)
As there is no vertical force that is the resultant is horizontal. Now for finding out point of application of resultant, Let resultant is at distance of 'd' from the point 'O'. Apply varignon's theorem, and by taking moment about point 'O'
R.d = 50 × 80 - 80 × 50 = 0
But ΣR = ΣH = -30N, so d = 0
d = 0, means point of application of the resultant is 'O'
Therefore an equivalent force 30N acts in negative x-axis at point 'O' which replaces the given force system.
Concept and application of limiting friction: Sol.: The maximum value of frictional force that comes into play, when the body just begins to slide over the surface of the ot
Various applications of numerical methods in the field of m=numerical engineering.
explain
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K = mE\3 (m-2)
Objectives After studying this section, you should be familiarized about: The typical job shop scheduling problem, Characteristics of computer controlled scheduling,
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