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Suppose A and B be two non-empty sets then every subset of A Χ B describes a relation from A to B and each relation from A to B is subset of AΧB.
Consider R : AΧB and (a, b) € R. then we can declare that a is associated to b by the relation R and write it as
a R b. If (a, b) ¢R, we write it as a b.
Example Let A {1, 2, 3, 4, 5}, B = {1, 3}
We set a relation from A to B as: a R b iff a ≤ b; a € A, b € B. Then
R ={(1, 1), (1, 3), (2, 3), (3, 3)}AΧB
2 -5power
First, see that the right hand side of equation (2) is a polynomial and thus continuous. This implies that this can only change sign if this firstly goes by zero. Therefore, if the
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interestind topic in operation research for doing project for msc mathematics
Solve for x , y (x + y - 8)/2 =( x + 2 y - 14)/3 = (3 x + y - 12 )/ 11 (Ans: x=2, y=6) Ans : x+ y - 8/2 = x + 2y - 14 /3 = 3x+ y- 12/11
differentiate x to the power 3
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