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Suppose A and B be two non-empty sets then every subset of A Χ B describes a relation from A to B and each relation from A to B is subset of AΧB.
Consider R : AΧB and (a, b) € R. then we can declare that a is associated to b by the relation R and write it as
a R b. If (a, b) ¢R, we write it as a b.
Example Let A {1, 2, 3, 4, 5}, B = {1, 3}
We set a relation from A to B as: a R b iff a ≤ b; a € A, b € B. Then
R ={(1, 1), (1, 3), (2, 3), (3, 3)}AΧB
Trace the curve (x/a)^3/2+(y/b)^2/3=1
why we study integration..?? uses
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Consider R be a relation from A to B, that is, take R A Χ B. Then Domain R = {a: a € A, (a, b) € R for any b € B} i.e. domain of R is the set of all the first components of
What is Identities and Contradictions ? Look at this equation: x + 1 = 1 + x It happens to be true always, no matter what the value of x. (Try it out! What if x is 43?)
How do I solve step by step 7
Obligatory application/interpretation problem : Next, we need to do our obligatory application/interpretation problem so we don't forget about them. Example : Assume that the
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