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Consider the relation schemas as follows.
works (person name, company name, salary); lives (person name, street, city); located in(company name, city); managers (person name, manager name); where manager name refers to person name.
Express the following queries firstly using Relational Algebra and then using SQL.
i) Find the names of the persons who work for company 'FBC' (company name= ‘FBC').
ii) List the names of the persons who work for company ‘FBC' along with the cities they live in.
iii) Find the persons who work for company ‘FBC' with a salary of more than 10000. List the names of these persons along with the streets and cities where they live.
iv) Find the names of the persons who live and work in the same city.
v) Find the names of the persons who do not work for company ‘FBC'.
Which two tools are used to administer users for Active Directory?
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In tuple relational calculus P1 → P2 is equivalent to ? A In tuple relational calculus P1→ P2 is equivalent to ¬P1 V P2. (The logical implication expression A B, meaning
Example : Create a sequence named SEQSS that starts at 105, has a step of 1 and can take maximum value as 2000. CREATE SEQUENCE SEQSS START WITH 105 INCREMENT BY 1 MAX VA
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Different stages of DDLC ?
Synonyms It allows short names or alternative names for objects. Example : CREATE SYNONYM D30 FOR EMPD30; Now if we give command:
Consider the relations EMP(ENO,ENAME,AGE,BASIC_SALARY) WORK_IN(ENO,DNO) DEPT(DNO,DNAME,CITY) Express the following queries in SQL (i) Find names of employees who work in a dep
how to implement hyrise in C plus plus
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