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Consider the relation schemas as follows.
works (person name, company name, salary); lives (person name, street, city); located in(company name, city); managers (person name, manager name); where manager name refers to person name.
Express the following queries firstly using Relational Algebra and then using SQL.
i) Find the names of the persons who work for company 'FBC' (company name= ‘FBC').
ii) List the names of the persons who work for company ‘FBC' along with the cities they live in.
iii) Find the persons who work for company ‘FBC' with a salary of more than 10000. List the names of these persons along with the streets and cities where they live.
iv) Find the names of the persons who live and work in the same city.
v) Find the names of the persons who do not work for company ‘FBC'.
Primary Index In primary index, there is a one-to-one relationship among the entries in the index table and the records in the major table. Primary index can be of two types:
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Data Control The data control mostly refers to commands that permit system and data privileges to be passed to several users. These commands are usually available to database admi
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Which is an advantage of view? The Advantages of view is Data security, Derived columns and Hiding of complex queries
Equi Join: A join in which the joining condition is based on equality among values in the common columns. Common columns show (redundantly) in the result table. Let us Consider th
Project Description: Oracle Certified Professional with 20 years of practice, Oracle version 6.0.34, 7.3, 8.0, 8i, 9i, 10G, 11G, 12C. Crossplatform migration, Informix, MSSql
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Write an sql statement to find what is the percentage of home policies which are from the state of Arizona out of all Home policies by Policy Value.
What is the use of with clause in SQL? The with clause gives a way of defining a temporary view whose explanation is available only to the query in which the with clause occurs
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