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Let u = sin(x). Then du = cos(x) dx. So you can now antidifferentiate e^u du. This is e^u + C = e^sin(x) + C. Then substitute your range 0 to pi. e^sin (pi)-e^sin(0) =0-0 =0
1. Write two m-files, one for the bisection method and another for Newton's method. 2. Using both the Bisection method and the Newton method answer the following: Include th
Negative Skewness It is an asymmetrical curve whether the long tail extends to the left NB: In developed countries this frequency curve for the age distribution is charact
if two circles O and O''intersect in two points, A and B, the the line segment OO is what?
pythagoras theorem
Let E; F be 2 points in the plane, EF has length 1, and let N be a continuous curve from E to F. A chord of N is a straight line joining 2 points on N. Prove if 0 and N has no cho
You are given that the total frequency is 900 and the median 100.48. From the following frequency distribution, find the class frequencies that are missing. Intelligence No. of Int
Initial Conditions and Boundary Conditions In many problems on integration, an initial condition (y = y 0 when x = 0) or a boundary condition (y = y
Sketch the graph of y = ( x -1) 2 - 4 . Solution Now, it is a parabola .Though, we haven't gotten that far yet and thus we will have to select
Prove the subsequent Boolean expression: (x∨y) ∧ (x∨~y) ∧ (~x∨z) = x∧z Ans: In the following expression, LHS is equal to: (x∨y)∧(x∨ ~y)∧(~x ∨ z) = [x∧(x∨ ~y)] ∨ [y∧(x∨
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