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Register Organization of 8086
8086 has a great set of registers containing special purpose and general purpose registers. All the 8086 resisters are 16-bit registers. The general purpose registers, may be utilized as either16-bit registers8 or -bit registers. The general purpose registers are either used for holding variables, data and intermediate results temporarily or for the other purposes like as counter or for storing offset address for some specific addressing modes etc. The special purpose registers are utilized as pointers, segment registers, offset storage registers for particular addressing modes or asindex registers. We will categorize the register set into 4 groups that are: General data Registers, Segment Registers, Pointer ad Index Registers, Flag Registers.
1. Write an assembly program that adds the elements in the odd indices of the following array. Use LOOP. What is the final value in the register? array1 DWORD 10, 20, 30, 40, 50, 6
64-bit integer calculator, which processes using 16-bits at a time (reg/mem16 operands)
Example : Add the contents of the 2000H: 0500H memory location to contents of 3000H: 0600H and store the result in 5000H: 0700H. Solution : Unlike the past example progra
DMA controller : Steps include in transferring a block of data from I/O devices (for example a disk) to memory: 1. CPU sends a signal to initiate disk transfe
MyLocation SDWORD 14 TheTest SDWORD 8 mov eax,MyLocation mov ebx,TheTest neg eax,ebx sub eax,ebx Show exactly what lives in eax after executi
Cache Memory Caching is a technology based on the memory subsystem of any computer. The majoraim of a cache is to accelerate the computer while keeping the cost of the computer
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need algorithm for multiplication in assembly with out mul function?
Write Policy A write policy determines how the cache deals with a write cycle. The 2 common write policies areWrite-Throughand Write-Back. In Write-Back policy, the cache behav
You have to write a subroutine (assembly language code using NASM) for the following equation. Dx= ax2+(ax-1)+2*(ax+2)/2
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