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Reason for why limits not existing : In the previous section we saw two limits that did not.
We saw that
did not exist since the function did not settle down to a single value as t approached t = 0 . The closer to t = 0 we moved the more passionately the function oscillated & in order for a limit to exist the function have to settle down to a single value.
However we saw that did not present not since the function didn't settle down to a single number as we moved in towards t = 0 , but rather then because it settled into two distinct numbers based on which side of t = 0 we were on.
The problem was that, as we approached t =0 , the function was moving in towards different numbers on each of the side.
8sinx-cosx=4
Computation of Covariance Ungrouped Data For a population consisting of paired ungrouped data points {X, Y} where,
the first question should be done using the website given (www.desmos.com/calculator )and another good example to explain using the graph ( https://www.desmos.com/calculator/ydimzr
We have seen that if y is a function of x, then for each given value of x, we can determine uniquely the value of y as per the functional relationship. For some f
How do you find the maxima or minima on a parabolic graph?
A radioactive substance decays to 30% of its original mass in 15 months. Determine the half-life of this radioactive substance to the nearest month
example and about this
w/ You could use this sample code to test your C functions // Please make appropriate changes to use this for C++. // Following main function contains 3 representative test cases
Which number falls among 5.56 and 5.81? If you add a zero to the end of 5.6 to get 5.60, it is simpler to see that 5.56
Use an appropriate infinite series method about x = 0 to find two solutions of the given differential equation: y''''-xy''-y=0
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