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Reason for why limits not existing : In the previous section we saw two limits that did not.
We saw that
did not exist since the function did not settle down to a single value as t approached t = 0 . The closer to t = 0 we moved the more passionately the function oscillated & in order for a limit to exist the function have to settle down to a single value.
However we saw that did not present not since the function didn't settle down to a single number as we moved in towards t = 0 , but rather then because it settled into two distinct numbers based on which side of t = 0 we were on.
The problem was that, as we approached t =0 , the function was moving in towards different numbers on each of the side.
Differentiate following. f ( x ) = sin (3x 2 + x ) Solution It looks as the outside function is the sine & the inside function is 3x 2 +x. The derivative is then.
Chain Rule : If f(x) and g(x) are both differentiable functions and we describe F(x) = (f. g)(x) so the derivative of F(x) is F′(x) = f ′(g(x)) g′(x). Proof We will s
how to answer this: 3x2-18x-60
which shows the rate 12 inches of rain in 6 hours as a unit rate
Also, their inability to apply the algorithm for division becomes quite evident. The reason for these difficulties may be many. We have listed some of them below. 1) There are n
JUST IS WHOLE
Compute the volume and surface area of a right circular cone: Compute the volume and surface area of a right circular cone along with r = 3", h = 4", and l = 5". Be sure to
5a^2b^2-5ab(6)
Explain Combining Negative Signs in integers? You've learned about positive and negative integers. BASICS : When you place a negative sign in front of an integer, you get
the formulas of the area of solid figures
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