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Reason for why limits not existing : In the previous section we saw two limits that did not.
We saw that
did not exist since the function did not settle down to a single value as t approached t = 0 . The closer to t = 0 we moved the more passionately the function oscillated & in order for a limit to exist the function have to settle down to a single value.
However we saw that did not present not since the function didn't settle down to a single number as we moved in towards t = 0 , but rather then because it settled into two distinct numbers based on which side of t = 0 we were on.
The problem was that, as we approached t =0 , the function was moving in towards different numbers on each of the side.
Explain Comparing Mixed Numbers in maths? A mixed number is made up of two parts: a whole number and a fraction. For example: 2(3/4) 2(3/4) is read "two and three-fourths
A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball is double that of a red ball , determine the number of blue balls in the bag.
jack and his mother paid $11.50 for tickets to the movies. An adult''s ticket costs $4.50 more than a child''s ticket. What was the cost of each ticket?
Q. How to Subtract fractions involving negative numbers? Ans. This is the same as adding them, but just remember the rule that two negatives on the same fraction cancel ou
i need help
Prove that Prim's algorithm produces a minimum spanning tree of a connected weighted graph. Ans: Suppose G be a connected, weighted graph. At each iteration of Prim's algorithm
Solution by Factorization, please solve quadratic equations by Factorization.
Sketch the feasible region for the following set of constraints: 3y - 2x ≥ 0 y + 8x ≤ 53 y - 2x ≤ 2 x ≥ 3. Then find the maximum and minimum values of the objective
Larry earned $32,000 per year. Then he received a (3)1/4% rise. What is Larry's salary after the raise? If Larry earns a (3) 1/4 % (or 3.25%) raise, he will earn 103.25% of his
Find no. of non negative integral solutions x 1 +x 2 +x 3 +4x 4 =20 Solution) 140. Break them into prime factors . Put 4 = 2^2 and every variable will have factors in 2,3,5 with
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