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Reason for why limits not existing : In the previous section we saw two limits that did not.
We saw that
did not exist since the function did not settle down to a single value as t approached t = 0 . The closer to t = 0 we moved the more passionately the function oscillated & in order for a limit to exist the function have to settle down to a single value.
However we saw that did not present not since the function didn't settle down to a single number as we moved in towards t = 0 , but rather then because it settled into two distinct numbers based on which side of t = 0 we were on.
The problem was that, as we approached t =0 , the function was moving in towards different numbers on each of the side.
core competency vs diversification
1/8 +2 3/4
the traffic light at three different road crossing change after every 48 seconds, 72 seconds and 108 seconds respectively. if they change simultaneously at 7 a.m., at what time wil
Solve 6 sin ( x/2)= 1 on [-20,30] Solution Let's first work out calculator of the way since that isn't where the difference comes into play. sin( x/2)= 1/6 ⇒x/2= sin
2 of 10 =
Question. Determine the position and nature of stationary points of the function? f(x,y)= y/x -x 2 +y 2
In parallelogram ABCD, m∠A = 3x + 10 and m∠D = 2x + 30, Determine the m∠A. a. 70° b. 40° c. 86° d. 94° d. Adjacent angles in a parallelogram are supplementary. ∠A a
the number is 605176 the underline digit is 0
Solve the inequality |x - 1| + |x - 2|≤ 3. Working Rule: First of all measure the expression to zero whose modulus happens in the given inequation and from this search the va
I need help trying to compare 10/15 and 8/12
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