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Reason for why limits not existing : In the previous section we saw two limits that did not.
We saw that
did not exist since the function did not settle down to a single value as t approached t = 0 . The closer to t = 0 we moved the more passionately the function oscillated & in order for a limit to exist the function have to settle down to a single value.
However we saw that did not present not since the function didn't settle down to a single number as we moved in towards t = 0 , but rather then because it settled into two distinct numbers based on which side of t = 0 we were on.
The problem was that, as we approached t =0 , the function was moving in towards different numbers on each of the side.
number of consonants to the number of letters in the English Alphabet express answer in ratio
In a parallelogram ABCD AB=20cm and AD=12cm.The bisector of angle A meets DC at E and BC produced at F.Find the length of CF.
Vector Arithmetic In this part we need to have a brief discussion of vector arithmetic. Addition We will begin with addition of two vectors. Thus, given the vectors a
The C.P. of 20 articles is same as theS.P. of x articles.Article profit is 25%.Find x
Carmen bought 3 pounds of bananas for $1.08. June paid for her purchase of bananas. If they paid the same price per pound, how many pounds did June buy?
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using v=g/k(1-e^-kt) find the velocity of the skydiver when k is 0.015
Definition 1. Given any x 1 & x 2 from an interval I with x 1 2 if f ( x 1 ) 2 ) then f ( x ) is increasing on I. 2. Given any x 1 & x 2 from an interval
solve: 4ydx+xdy=0
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