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Reason for why limits not existing : In the previous section we saw two limits that did not.
We saw that
did not exist since the function did not settle down to a single value as t approached t = 0 . The closer to t = 0 we moved the more passionately the function oscillated & in order for a limit to exist the function have to settle down to a single value.
However we saw that did not present not since the function didn't settle down to a single number as we moved in towards t = 0 , but rather then because it settled into two distinct numbers based on which side of t = 0 we were on.
The problem was that, as we approached t =0 , the function was moving in towards different numbers on each of the side.
Two circles touching internally at O. OXY, OAB straight lines, the latter passing through the centres. Prove that OX : OY = OA : OB. Given : Two circles touching internally a
In a parallelogram ABCD AB=20cm and AD=12cm.The bisector of angle A meets DC at E and BC produced at F.Find the length of CF.
Catalans Conjecture
Write a function that computes the product of two matrices, one of size m × n, and the other of size n × p. Test your function in a program that passes the following two matrices t
Find out primes of each denominator: Add 1/15 and 7/10 Solution: Step 1: Find out primes of each denominator. 15 = 5 x 3 10 = 5 x 2 Step 2:
If X = {a, e, i, o, u} and Y = {a, b, c, d, e}, then what is Y - X ?
The Fisher's index The index of Fisher acts as a compromise between Paasche' index and Laspeyre's index. This is calculated as a geometric mean of the two indexes.
If roots of (x-p)(x-q) = c are a and b what will be the roots of (x-a)(x-b) = -c please explain. Solution) (x-p)(x-q)=c x2-(p+q)x-c=0 hence, a+b=p+q and a.b=pq-c
1. Using suffix trees, give an algorithm to find a longest common substring shared among three input strings: s 1 of length n 1 , s 2 of length n 2 and s 3 of length n 3 .
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