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Reason for why limits not existing : In the previous section we saw two limits that did not.
We saw that
did not exist since the function did not settle down to a single value as t approached t = 0 . The closer to t = 0 we moved the more passionately the function oscillated & in order for a limit to exist the function have to settle down to a single value.
However we saw that did not present not since the function didn't settle down to a single number as we moved in towards t = 0 , but rather then because it settled into two distinct numbers based on which side of t = 0 we were on.
The problem was that, as we approached t =0 , the function was moving in towards different numbers on each of the side.
How do i add 4+2
19 times 5
2.When investigating times required for drive-through service, the following results (in seconds) were obtained. Find the range, variance, and standard deviation for each of the tw
WON 5 GAMES
The two sides of a triangle are 17 cm and 28 cm long, and the length of the median drawn to the third side is equal to 19.5 cm. Find the distance from an endpoint of this median to
1. Using given data set (Assignment_1data in the folder) a) Make scatterplot between "Years since first marriage" and "Total children ever born" b) Make scatterplot between
(a+b+c)2=
How many square centimeters are in one square meter? There are 100 cm in a meter. A square meter is 100 cm through 100 cm. The area of this is 10,000 sq cm (100 × 100 = 10,000)
help
Fundamental Theorem of Calculus, Part I If f(x) is continuous on [a,b] so, g(x) = a ∫ x f(t) dt is continuous on [a,b] and this is differentiable on (a, b) and as,
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