Real distinct solutions, Algebra

Assignment Help:

By Using the discriminant find out which solution set we obatin for each of the following quadratic equations.

                                          13x2 +1= 5x

Solution

Firstly get the equation in standard form.

13x2 - 5x + 1 = 0

 

Then we have,

a = 13             b = -5 c=1

Plugging in the discriminant gives,

                  b2 - 4ac = ( -5)2  - 4 (13) (1) =-27

The discriminant is negative & thus we will have two complex solutions.  For reference reason the actual solutions are,

1542_Real distinct solutions.png


Related Discussions:- Real distinct solutions

Rational Expressions, I''m having trouble with this problem..t squared-16 d...

I''m having trouble with this problem..t squared-16 divided by t squared minus-t-20

Equations with more than one variable, Here we'll be doing is solving equat...

Here we'll be doing is solving equations which have more than one variable in them.  The procedure that we'll be going through here is very alike to solving linear equations that i

Student, find the level of illumination for four fixtures rated at 2800 lum...

find the level of illumination for four fixtures rated at 2800 lumens each if the coefficient of depreciation is 0.75, the coefficient of utilization is 0.6, and the area of the ro

Inequality problem, why is the inequality symbol must be reversed when both...

why is the inequality symbol must be reversed when both sides of a inequality are multiplied or divided by a negative number

AS/A2 Coursework, I need to do a coursework for math but do not know what t...

I need to do a coursework for math but do not know what to do?

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd