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By Using the discriminant find out which solution set we obatin for each of the following quadratic equations.
13x2 +1= 5x
Solution
Firstly get the equation in standard form.
13x2 - 5x + 1 = 0
Then we have,
a = 13 b = -5 c=1
Plugging in the discriminant gives,
b2 - 4ac = ( -5)2 - 4 (13) (1) =-27
The discriminant is negative & thus we will have two complex solutions. For reference reason the actual solutions are,
s-1.75=0.02
i dont know how to do this equation y=x+3 2x+y=6
f(2)=3 and g(x)=x^2+1 then gof(2)
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