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By Using the discriminant find out which solution set we obatin for each of the following quadratic equations.
13x2 +1= 5x
Solution
Firstly get the equation in standard form.
13x2 - 5x + 1 = 0
Then we have,
a = 13 b = -5 c=1
Plugging in the discriminant gives,
b2 - 4ac = ( -5)2 - 4 (13) (1) =-27
The discriminant is negative & thus we will have two complex solutions. For reference reason the actual solutions are,
how do you find the solution using linear combinations 4x+3y=-1 and -3x+-5y=9
Give all solutions of the nonlinear system of equations including those with nonreal complex compents: xy=-20 3x+5y=5
Domain and Range The domain of any equation is the set of all x's which we can plug in the equation & get back a real number for y. The range of any equation is the set of all
4x^2+8x-16=0
x+y=0 x=y+4
17b-29=39
the sum of three consecutive odd integers is -195. find the three integers.
what is the expression. Of 1=1/2n(3n-1)
what is 10037+3443=
(2/9+4/9)(1/3-5/8)
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