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By Using the discriminant find out which solution set we obatin for each of the following quadratic equations.
13x2 +1= 5x
Solution
Firstly get the equation in standard form.
13x2 - 5x + 1 = 0
Then we have,
a = 13 b = -5 c=1
Plugging in the discriminant gives,
b2 - 4ac = ( -5)2 - 4 (13) (1) =-27
The discriminant is negative & thus we will have two complex solutions. For reference reason the actual solutions are,
Given that x=2 is a zero of P ( x ) = x 3 + 2x 2 - 5x - 6 determine the other two zeroes. Solution Firstly, notice that we actually can say the other two since we know th
Actually here we're not going to look at a general cubic polynomial. Here we are jsut going to look at f ( x ) = x 3 . Really there isn't much to do here other than only plugging
how do you solve x5 * x3
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I am trying to figure out how the tree method works for number 47
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