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By Using the discriminant find out which solution set we obatin for each of the following quadratic equations.
13x2 +1= 5x
Solution
Firstly get the equation in standard form.
13x2 - 5x + 1 = 0
Then we have,
a = 13 b = -5 c=1
Plugging in the discriminant gives,
b2 - 4ac = ( -5)2 - 4 (13) (1) =-27
The discriminant is negative & thus we will have two complex solutions. For reference reason the actual solutions are,
If the rational number x= b/ c is a zero of the n th degree polynomial, P ( x ) = sx n + ...........+ t Where every the coefficients are
square root o f 34
how do you do it i do not understand at all
I need Help.
The "humps" where the graph varies direction from increasing to decreasing or decreasing to increasing is frequently called turning points . If we know that the polynomial con
simplify the following expressions for the given values x3 -x2/x2 -x x=3 how do i do this to get answer need step by step instruction
Example Solve out each of the following equations. 7 x = 9 Solution Okay, although we say above that if we contained a logarithm in fron
5x+2x-17=53
1.(x+y+1)² 2.(x+y-1)² 3.(x-y-1)² 4.(-x-y-1)² question: what is the effect of switching the plus sign to minus sign on the product
Given f ( x ) = 2 + 3x - x 2 and g ( x ) = 2 x -1 evaluate ( f + g ) ( 4) Solution Through evaluate we mean one of two things based on what is in the parenthesis. If the
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