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Now we have to start looking at more complicated exponents. In this section we are going to be evaluating rational exponents. i.e. exponents in the form
b m/n
where m and n both are integers.
We will begin simple by looking at the given special case,
b1/ n
where n refer to an integer. Once we have figured out the more general case provided above will in fact be pretty simple to deal with.
Let's first described just what we mean by exponents of this form.
a= b 1/n is equivalent to an =b
In other terms, when evaluating b 1/n, we are actually asking what number (in this case a) did we rise to the n to get b. Frequently b 1/n is called the nth root of b.
Let u = sin(x). Then du = cos(x) dx. So you can now antidifferentiate e^u du. This is e^u + C = e^sin(x) + C. Then substitute your range 0 to pi. e^sin (pi)-e^sin(0) =0-0 =0
Write a procedure to obtain the inverse of an n by n matrix usingGaussian elimination. (You cannot use A - 1 or any of the built-in packages like 'MatrixInverse'.) Output any a
sin30
need answer to integers that equal 36
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