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Ratio of belt tension:
For Open belt drive:
Angle of contact (θ) for larger pulley = ∏ + 2α Angle of contact (θ) for smaller pulley = ∏ - 2α For cross belt drive:
Angle of contact (θ) for larger pulley = ∏ + 2α
Angle of contact (θ) for smaller pulley = ∏ + 2α
(that is for both the pulley, it is same)
But for solving problems, we take the Angle of contact (θ) for smaller pulley
Hence,
Angle of contact (θ) = ∏ - 2α - for open belt
Angle of contact (θ) = ∏ + 2α - for cross belt
#question.needs help to do my assignment.
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