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what is number of quadratic equation that are unchanged by squaring their roots is There are four such cases x2 =0 root 0 (x-1)2=0 root 1 x(x+1)=0 roots 0 and 1 x2+x+1=0 roots ω and ω2 let x2 +bx +c=0 ............1 not let another equation whoose roots are square of this equation so X=x2 or x=√X put value of x X +b√X +c =0 or X +c =-b√X square X2 +c2 +2cX =b2X X2 +(2c-b2)X + c2 =0..................2 root of equation 2 is the square of root of equation 1 both equation will be same if their coefficient are in proportion 1/1 =b/(2c-b2) =c/c 2 b= 2c-b2 ................3 c=c2 ....................3 from equation 3 c=0 or 1 for c =0 b= 0 and -1 for c=1 b= 1 and -2 so four combination are possible
what is number of quadratic equation that are unchanged by squaring their roots is
There are four such cases x2 =0 root 0
(x-1)2=0 root 1
x(x+1)=0 roots 0 and 1
x2+x+1=0 roots ω and ω2
let x2 +bx +c=0 ............1
not let another equation whoose roots are square of this equation
so X=x2 or x=√X
put value of x
X +b√X +c =0
or X +c =-b√X
square
X2 +c2 +2cX =b2X
X2 +(2c-b2)X + c2 =0..................2
root of equation 2 is the square of root of equation 1
both equation will be same if their coefficient are in proportion
1/1 =b/(2c-b2) =c/c 2
b= 2c-b2 ................3
c=c2 ....................3
from equation 3 c=0 or 1
for c =0 b= 0 and -1
for c=1 b= 1 and -2
so four combination are possible
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sir kindly guide me in 1st order linear equations.
If you find nothing out of this rapid review of linear algebra you should get this section. Without this section you will not be capable to do any of the differential equations wo
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