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what is number of quadratic equation that are unchanged by squaring their roots is There are four such cases x2 =0 root 0 (x-1)2=0 root 1 x(x+1)=0 roots 0 and 1 x2+x+1=0 roots ω and ω2 let x2 +bx +c=0 ............1 not let another equation whoose roots are square of this equation so X=x2 or x=√X put value of x X +b√X +c =0 or X +c =-b√X square X2 +c2 +2cX =b2X X2 +(2c-b2)X + c2 =0..................2 root of equation 2 is the square of root of equation 1 both equation will be same if their coefficient are in proportion 1/1 =b/(2c-b2) =c/c 2 b= 2c-b2 ................3 c=c2 ....................3 from equation 3 c=0 or 1 for c =0 b= 0 and -1 for c=1 b= 1 and -2 so four combination are possible
what is number of quadratic equation that are unchanged by squaring their roots is
There are four such cases x2 =0 root 0
(x-1)2=0 root 1
x(x+1)=0 roots 0 and 1
x2+x+1=0 roots ω and ω2
let x2 +bx +c=0 ............1
not let another equation whoose roots are square of this equation
so X=x2 or x=√X
put value of x
X +b√X +c =0
or X +c =-b√X
square
X2 +c2 +2cX =b2X
X2 +(2c-b2)X + c2 =0..................2
root of equation 2 is the square of root of equation 1
both equation will be same if their coefficient are in proportion
1/1 =b/(2c-b2) =c/c 2
b= 2c-b2 ................3
c=c2 ....................3
from equation 3 c=0 or 1
for c =0 b= 0 and -1
for c=1 b= 1 and -2
so four combination are possible
Find the second derivative of the below given equation Y= e x cosx
Q. How to calculate arithmetic average or mean? Ans. When people collect information, or data, they can easily be overwhelmed with information. Just imagine listing the b
If A = 100 and B = 44 then A1 = 120 and B2 = 52.80 A is MAP and B is Tier 6. I need help to find a simple equation that I just cannot find. I just need the percentage
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what is the first step
IN THIS WE HAVE TO ADD THE PROBABILITY of 3 and 5 occuring separtely and subtract prob. of 3 and 5 occuring together therefore p=(166+100-33)/500=233/500=0.466
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