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If roots of (x-p)(x-q) = c are a and bwhat will be the roots of (x-a)(x-b) = -c please explain?Ans) (x-p)(x-q)=cx2-(p+q)x-c=0hence, a+b=p+q and a.b=pq-c a.b+c=p.qby solving other eq we getx2-(a+b)x+ab+c=0thus sum of roots=a+b=p+q product of roots=a.b+c=p.qhence its roots are pand q
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Logarithmic form and exponential form ; We'll begin with b = 0 , b ≠ 1. Then we have y= log b x is equivalent to x= b y The first one is called
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