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If roots of (x-p)(x-q) = c are a and bwhat will be the roots of (x-a)(x-b) = -c please explain?Ans) (x-p)(x-q)=cx2-(p+q)x-c=0hence, a+b=p+q and a.b=pq-c a.b+c=p.qby solving other eq we getx2-(a+b)x+ab+c=0thus sum of roots=a+b=p+q product of roots=a.b+c=p.qhence its roots are pand q
Determine all possible solutions to the subsequent IVP. y' = y ? y(0) = 0 Solution : First, see that this differential equation does NOT satisfy the conditions of the th
a. Estimate the following model, C t = β 0 + β 1 * DI t + ε t Where C t = Aggregate Consumption Expenditure in Australia, quarterly data for the per
An orange has a diameter of 3 inches. Evaluate the volume of one orange. (π = 3.14) a. 9.42 in 3 b. 113.04 in 3 c. 28.26 in 3 d. 14.13 in 3 d. To determine the
Differentiate following functions. h (t ) = 2t 5 + t 2 - 5 / t 2 We can simplify this rational expression as follows. h (t )
A mortgage lender seeks to maximize the expected value of its portfolio. The portfolio, of course, is the sum of all of the mortgages in it, so no generality is lost by examining t
Definite integration It involve integration among specified limits, say a and b The integral is a definite integral whether the limits of integration are as: a and b
Two sessions of swimming lessons were held at a pool. In the first session 40 students attended. Of these 40 students 60% were girls. How many girls attended the first session of s
Substitution Rule Mostly integrals are fairly simple and most of the substitutions are quite simple. The problems arise in correctly getting the integral set up for the substi
lecturer notes
Suppose S = {vi} and T = {ti} are "easy" sets of knapsak weight. Also, P and q are primes p > ?Si and q > ?ti. We can combine S and T into a signle set of knapsack weight as follow
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