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If roots of (x-p)(x-q) = c are a and bwhat will be the roots of (x-a)(x-b) = -c please explain?Ans) (x-p)(x-q)=cx2-(p+q)x-c=0hence, a+b=p+q and a.b=pq-c a.b+c=p.qby solving other eq we getx2-(a+b)x+ab+c=0thus sum of roots=a+b=p+q product of roots=a.b+c=p.qhence its roots are pand q
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Before going to solving differential equations we must see one more function. Without Laplace transforms this would be much more hard to solve differential equations which involve
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In the earlier section we looked at first order differential equations. In this section we will move on to second order differential equations. Just as we did in the previous secti
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