Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
If roots of (x-p)(x-q) = c are a and bwhat will be the roots of (x-a)(x-b) = -c please explain?Ans) (x-p)(x-q)=cx2-(p+q)x-c=0hence, a+b=p+q and a.b=pq-c a.b+c=p.qby solving other eq we getx2-(a+b)x+ab+c=0thus sum of roots=a+b=p+q product of roots=a.b+c=p.qhence its roots are pand q
Kyra receives a 5% commission on every car she sells. She received a $1,325 commission on the last car she sold. What was the cost of the car? Use the proportion part/whole =
Derivative for Parametric Equations dx/dy = (dx/dt) / (dy/dt) , given dy/dt ≠ 0 Why would we wish to do this? Well, remind that in the arc length section of the Appl
what all can be the table contents for my maths project on shares and dividend
Properties of Cross product If u, v and w are vectors and c is a number then u → * v → = -v → * w → (cu → ) * v → =
Explain English System in details? There are three types of measurements that can be taken using the English System: length, distance, weight, and capacity. Length and dista
6 divided by 678
It is the last case that we require to take a look at. During this section we are going to look at solutions to the system, x?' = A x? Here the eigenvalues are repeated eigen
Properties of Dot Product - proof Proof of: If v → • v → = 0 then v → = 0 → This is a pretty simple proof. Let us start with v → = (v1 , v2 ,.... , vn) a
I need help fast with my calculus work
The sum of areas of two squares is 468m 2 If the difference of their perimeters is 24cm, find the sides of the two squares. Ans: Let the side of the larger square be x .
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd