Pythagorean theorem, Mathematics

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How do you find the perimeter of an irregular shape using Pythagorean theorem?

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Utilizes the definition of the limit to prove the given limit. Solution Let M > 0 be any number and we'll have to choose a δ > 0 so that, 1/ x 2   > M

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1/a+b+x  =1/a+1/b+1/x    a+b ≠ 0 Ans: 1/a+b+x  =1/a+1/b+1/x => 1/a+b+x -1/x = +1/a +1/b ⇒  x - ( a + b + x )/ x ( a + b + x )   = + a + b/ ab ⇒

Evalute right-hand limit, Evaluate following limits. Solution ...

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