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Q.Prove using Boolean Algebra
1. X (X+Y) = X
2. AB + AC + BC' = AC + BC'
3. (A+B+C) (A+B'+C') (A+B+C') (A+B'+C)=A
4. (A+B'+C) (AB+A'C) = (A+C) (A'+B)
5. XY + XZ + YZ' = XZ + YZ'
Evaluation function - canonical genetic algorithm: However note that this termination check may be related or the same as the evaluation function - that discussed later - but
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