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Q.Prove using Boolean Algebra
1. X (X+Y) = X
2. AB + AC + BC' = AC + BC'
3. (A+B+C) (A+B'+C') (A+B+C') (A+B'+C)=A
4. (A+B'+C) (AB+A'C) = (A+C) (A'+B)
5. XY + XZ + YZ' = XZ + YZ'
Prove the following Boolean identities using the laws of Boolean algebra (A + B)(A + C) = A + BC Ans. (A+B)(A+C)=A+BC LHS AA+AC+AB+BC=A+AC+AB+BC OR A((C+1)+A(B+1))+BC
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