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Q. Prove using Boolean Algebra
1. AB + AC + BC' = AC + BC'
2. (A+B+C) (A+B'+C') (A+B+C') (A+B'+C)=A
3. (A+B) (A'+B'+C) + AB = A+B
4. A'C + A'B + AB'C + BC = C + A'B
How many two input AND gates and two input OR gates are required to realize Y = BD+CE+AB ? Ans. Here three product terms, therefore three AND gates of two inputs are needed.
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