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Q. Prove using Boolean Algebra
1. AB + AC + BC' = AC + BC'
2. (A+B+C) (A+B'+C') (A+B+C') (A+B'+C)=A
3. (A+B) (A'+B'+C) + AB = A+B
4. A'C + A'B + AB'C + BC = C + A'B
The decimal equivalent of (1100) 2 is ? Ans. (1100) 2 = (12) 10
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SOLVE PUSH+DOOR=BELL AND GIVE+THEM=HELP
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