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Prove the equations A + A‾ .B + A.B‾ = A + B using the Boolean algebraic theorems ?
Ans. The equation is A + A‾.B + A.B‾ = A + BL.H.S. = A + A‾ .B + A.B‾= (A + A.B‾) + A‾.B= A (1+ B‾) + A‾.B= A + A‾ .B (? 1+B‾ =1)= (A +A‾ ) (A + B)= (A + B) (? A + A‾ = 1)= R.H.SThus Proved
Divide overflow is generated when (A) Sign of the dividend is dissimilar from that of divisor. (B) Sign of the dividend is same as that of divisor. (C) The first part
decode the code
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