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If secA= x+1/4x, prove that secA+tanA=2x or 1/2x.
Ans: Sec? = x + 1/4x
⇒ Sec2? =( x + 1/4x)2 (Sec2?= 1 + Tan2?)
Tan2? = ( x + 1/4x)2-1
Tan2? = ( x - 1/4x)2
Tan? = + x - 1/4x
Sec? + Tan? = x + 1/4x + x-1/4x
=2x or 1/2x
IN THIS WE HAVE TO ADD THE PROBABILITY of 3 and 5 occuring separtely and subtract prob. of 3 and 5 occuring together therefore p=(166+100-33)/500=233/500=0.466
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