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Prove that sec2θ+cosec2θ can never be less than 2.
Ans: S.T Sec2θ + Cosec2θ can never be less than 2.
If possible let it be less than 2.
1 + Tan2θ + 1 + Cot2θ < 2.
⇒ 2 + Tan2θ + Cot2θ
⇒ (Tanθ + Cotθ)2 < 2.
Which is not possible.
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Evaluate following indefinite integrals. (a) ∫ 5t 3 -10t -6 + 4 dt (b) ∫ dy Solution (a) ∫ 5t 3 -10t -6 + 4 dt There's not whole lot to do here other than u
x=±4, if -2 = y =0 x=±2, if -2 = y = 0
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Use the definition of the limit to prove the given limit. Solution Let ε> 0 is any number then we have to find a number δ > 0 so that the following will be true. |
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