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Prove that sec2θ+cosec2θ can never be less than 2.
Ans: S.T Sec2θ + Cosec2θ can never be less than 2.
If possible let it be less than 2.
1 + Tan2θ + 1 + Cot2θ < 2.
⇒ 2 + Tan2θ + Cot2θ
⇒ (Tanθ + Cotθ)2 < 2.
Which is not possible.
a triangle is 180
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