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Two tangents PA and PB are drawn to the circle with center O, such that ∠APB=120o. Prove that OP=2AP.
Ans: Given : - ∠APB = 120o Construction : -Join OP To prove : -OP = 2AP
Proof :- ∠APB = 120o
∴∠APO = ∠OPB = 60o
Cos 60o = AP/OP
1/2 = AP/OP
∴OP = 2AP
Hence proved
Given f ( x ) = 3x - 2 determine f -1 ( x ) . Solution Now, already we know what the inverse to this function is as already we've done some work with it. Though, it
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Translate the following formula into a prefix form expression in Scheme: 5+4*(6-7/5)/3(14-5)(3+1)
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how do u do it
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