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Two tangents PA and PB are drawn to the circle with center O, such that ∠APB=120o. Prove that OP=2AP.
Ans: Given : - ∠APB = 120o Construction : -Join OP To prove : -OP = 2AP
Proof :- ∠APB = 120o
∴∠APO = ∠OPB = 60o
Cos 60o = AP/OP
1/2 = AP/OP
∴OP = 2AP
Hence proved
3x+2y=6 x-y=7
4856+12334
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