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Two tangents PA and PB are drawn to the circle with center O, such that ∠APB=120o. Prove that OP=2AP.
Ans: Given : - ∠APB = 120o Construction : -Join OP To prove : -OP = 2AP
Proof :- ∠APB = 120o
∴∠APO = ∠OPB = 60o
Cos 60o = AP/OP
1/2 = AP/OP
∴OP = 2AP
Hence proved
pi to the ten-thousandths
x^2-5x+4 can written in roots as (x-1)*(x-4) x^2-4 can be written interms of (x-2)(x+2).so [(x-1)(x-4)/(x-2)(x+2)]
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