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Two tangents PA and PB are drawn to the circle with center O, such that ∠APB=120o. Prove that OP=2AP.
Ans: Given : - ∠APB = 120o Construction : -Join OP To prove : -OP = 2AP
Proof :- ∠APB = 120o
∴∠APO = ∠OPB = 60o
Cos 60o = AP/OP
1/2 = AP/OP
∴OP = 2AP
Hence proved
if 1/x+2, 1/x+3, 1/x+5 are in AP find x Ans 1/x+2,1/x+3, 1/x+5 are in AP find x. 1/x+3 - 1/x+2 = 1/x+5-1/x+3 => 1/x 2 +5x+6 = 2/ x 2 +8x +15 => On solving we get x
how it solved
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