Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
ABCD is a parallelogram in the given figure, AB is divided at P and CD and Q so that AP:PB=3:2 and CQ:QD=4:1. If PQ meets AC at R, prove that AR= 3/7 AC.
Ans: ΔAPR ∼ ΔCQR (AA)
⇒ AP/CQ = PR/QR = AR/CR
⇒ AP/CQ = AR /CR & AP= 3/5 AB
⇒ 3 AB/5CQ = AR/ CR & CQ= 4/5 CD = 4/5 AB
⇒ AR/CR = 3/4
⇒ CR/AR = 4/3
CR + AR/AR = 4 +1/3
⇒ AC/AR = 7/3
⇒ AR = 3/7 AC
Hence proved
Solve the subsequent IVP Y'' - 9 y = 0, y(0) = 2, y'(0) = -1 Solution First, the two functions y (t ) = e 3t and y(t ) = e -3t That is "nice enough" for us to
/3x-5/-x-7=0
Add 1011 and 1101 in base 2
how do you do hard math!!!
1x1
Core concept of marketing
How do you do converting metric units?
i have discovered a formula for finding the radius at any point of the graph have i done a good job
Sir before I applied for online assignment help job and the selection process is not complete for me. You sent me problem assignment before.But those problems were not completed.Ca
I've termed this section as Intervals of Validity since all of the illustrations will involve them. Though, there is many more to this section. We will notice a couple of theorems
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +1-415-670-9521
Phone: +1-415-670-9521
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd