Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
ABC is a right-angled isosceles triangle, right-angled at B. AP, the bisector of ∠BAC, intersects BC at P. Prove that AC2 = AP2 + 2(1+√2)BP2
Ans: AC = √2AB (Since AB = BC)
AB/AC = BP/CP (Bisector Theorem)
⇒ CP = √2 BP
AC2 - AP2 = AC2 - (AB2 + BP2)
= AC2 - AB2 - BP2
= BC2 - BP2
= (BP + PC)2 - BP2
= (BP + √2BP)2 - BP2
= 2BP2 + 2√2 BP2
= 2 ( √2 +1) BP2 ⇒ AC2 = AP2 + 2(1+√2)BP2
Proved
Business Applications In this section let's take a look at some applications of derivatives in the business world. For the most of the part these are actually applications wh
a-1/a =8 find
A telephone dialled is numbered 0to9. if 0is dialled first the caller is connected to the international exchange system.find the number of local calls that can be rung if a local n
reflection about index number in a creative way
square root of 78269
tan45 degrees=tan(90degrees-45degrees)
Proof of: lim q →0 (cos q -1) / q = 0 We will begin by doing the following, lim q →0 (cosq -1)/q = lim q →0 ((cosq - 1)(cosq + 1))/(q (cosq + 1)) = lim q
let X be a nonempty set. let x belong to X. show that the collection l={ union subset of X : union = empty or belong U
Suppose that, on a certain day, 495 passengers want to fly from Honolulu (HNL) to New York (JFK); 605 passengers want to fly from HNL to Los Angeles (LAX); and 1100 passengers want
Let G be a group acting on a set X. The action is called faithful if for any g ≠ 1 ∈ G there exists an x ∈ X such that gx ≠ x. That is, only the identity fi xes everything. Prov
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd