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If ABC is an obtuse angled triangle, obtuse angled at B and if AD⊥CB Prove that AC2 =AB2 + BC2+2BCxBD
Ans: AC2 = AD2 + CD2
= AD2 + (BC + BD)2
= AD2 + BC2 + 2BC.BD+BD2
= AB2 + BC2 + 2BC.BD
x^2 + 10x +2 4
what is 10 times 10 pls
Since we are going to be working almost exclusively along with systems of equations wherein the number of unknowns equals the number of equations we will confine our review to thes
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