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ABC is a right triangle right-angled at C and AC=√3 BC. Prove that ∠ABC=60o.
Ans: Tan B = AC/BC
Tan B = √3 BC/BC
Tan B =√3
⇒ Tan B = Tan 60
⇒ B = 60o
⇒ ∠ABC = 60o
Hence proved
Find the area of shaded region of circle of radius =7cm, if ∠AOB=70 o , ∠COD=50 o and ∠EOF=60 o . (Ans:77cm 2 ) Ans: Ar( Sector AOB + Sector COD + Sector OEF) = 7
Evaluate following limits. Solution Let's begin with the right-hand limit. For this limit we have, x > 4 ⇒ 4 - x 3 = 0 also, 4 - x → 0 as x → 4
3x2+5x-2
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One-sided limits: We do this along with one-sided limits. As the name implies, with one-sided limits we will just looking at one side of the point in question. Following are the
You are required to implement Kruskal's algorithm for finding a Minimum Spanning Tree of Graph. This will require implementing : A Graph Data Type (including a display meth
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Prove the subsequent Boolean expression: (x∨y) ∧ (x∨~y) ∧ (~x∨z) = x∧z Ans: In the following expression, LHS is equal to: (x∨y)∧(x∨ ~y)∧(~x ∨ z) = [x∧(x∨ ~y)] ∨ [y∧(x∨
(e) Solve the following system of equations by using Matrix method. 3x + 2y + 2z = 11 x + 4y + 4z = 17 6x + 2y + 6z = 22
(6x+9y) + (11x+13y)
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