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Prove that a simple graph is connected if and only if it has a spanning tree.
Ans: First assume that a simple graph G has a spanning tree T. T consists of every node of G. By the definition of a tree, there is a path among any two nodes of T. As T is a subgraph of G, there is a path among each pair of nodes in G. Hence G is connected.
Here now let G is connected. If G is a tree then nothing to prove. If G is not a tree, it must consist of a simple circuit. Let G has n nodes. We can choose (n - 1) arcs from G in such type of a way that they not form a circuit. It results into a subgraph comprising all nodes and only (n - 1) arcs. So by definition this subgraph is a spanning tree.
Decimal representations of some basic angles: As a last quick topic let's note that it will, on occasion, be useful to remember the decimal representations of some basic angles. S
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Solve 9 sin ( 2 x )= -5 cos(2x ) on[-10,0]. Solution At first glance this problem appears to be at odds with the sentence preceding the example. However, it really isn't.
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Need solution For the universal set T = {1, 2, 3, 4, 5} and its subset A ={2, 3} and B ={5, } Find i) A 1 ii) (A 1 ) 1 iii) (B 1 ) 1
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