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Prove that a simple graph is connected if and only if it has a spanning tree.
Ans: First assume that a simple graph G has a spanning tree T. T consists of every node of G. By the definition of a tree, there is a path among any two nodes of T. As T is a subgraph of G, there is a path among each pair of nodes in G. Hence G is connected.
Here now let G is connected. If G is a tree then nothing to prove. If G is not a tree, it must consist of a simple circuit. Let G has n nodes. We can choose (n - 1) arcs from G in such type of a way that they not form a circuit. It results into a subgraph comprising all nodes and only (n - 1) arcs. So by definition this subgraph is a spanning tree.
Find the Laplace transforms of the specified functions. (a) f(t) = 6e 5t + e t3 - 9 (b) g(t) = 4cos(4t) - 9sin(4t) + 2cos(10t) (c) h(t) = 3sinh(2t) + 3sin(2t)
how can solve limits
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number of consonants to the number of letters in the English Alphabet express answer in ratio
if I read 6 hours of spring break how many minutes did read
It is difficult to produce the individual answers and the insights that they were providing. But, let's look at some broad patterns that we found, which are similar to those that o
Ask question draw a line parallel to given line xy at a distance of 5cm from it #Minimum 100 words accepted#
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