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Prove that a simple graph is connected if and only if it has a spanning tree.
Ans: First assume that a simple graph G has a spanning tree T. T consists of every node of G. By the definition of a tree, there is a path among any two nodes of T. As T is a subgraph of G, there is a path among each pair of nodes in G. Hence G is connected.
Here now let G is connected. If G is a tree then nothing to prove. If G is not a tree, it must consist of a simple circuit. Let G has n nodes. We can choose (n - 1) arcs from G in such type of a way that they not form a circuit. It results into a subgraph comprising all nodes and only (n - 1) arcs. So by definition this subgraph is a spanning tree.
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Find the perimeter of the figure, where AED is a semi-circle and ABCD is a rectangle. (Ans : 76cm) Ans: Perimeter of the fig = 20 + 14 + 20 + length of the arc (AED
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Find the least number that is divisible by all numbers between 1 and 10 (both inclusive). Ans: The required number is the LCM of 1,2,3,4,5,6,7,8,9,10 ∴ LCM = 2 × 2
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