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Prove that a relation which is 4NF must be BCNF.
Ans Let R be in 4NF. Suppose it is not in BCNF. Hence, there exists an FD X→Y in R such that x is not a super key. Although by the rule M1 X→Y|=x→→Y. Once again x here is not a super key. This contradicts the fact that R is in 4NF. Hence, our assumption is false. Each R in 4NF should be in BCNF.
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Question: Consider the following database relations for a textbook ordering system used by a college bookshop: Book (b-copy#, bname, ISBN#, author, price, subject) Order (s#
ERD Diagram of Medical Recruitment Agency?
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how to implement mid square hashing?
Benefits: It limits data access. It makes difficult queries look easy. It permits data independence. It presents dissimilar views of the similar data.
List two restrictions that are applied on the modification (updation, insertion or deletion) of base tables through view. Ans: The two restrictions are: 1. If a view
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