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Prove the equations using the Boolean algebraic theorems that is given belowA‾BC + AB‾C + ABC‾+ ABC = AB + BC + ACAns. The equation given is A‾BC + AB‾C + ABC‾+ ABC = AB + BC + ACL.H.S = A‾BC + AB‾C + ABC‾+ ABC= A‾BC + AB‾C + AB (C +C‾)= A‾BC + AB‾C + AB (Q C + C‾ = 1)= A‾BC + A (B + B‾C)= A‾BC + A (B + C) (? B + B‾C = B + C)= A‾BC + A B + AC= C (A + A‾B) + AB + AC= C (A + B) + A B + AC (? A + A‾B = A + B)= AC + BC + AB + AC= AB + BC + AC (? AC + AC = AC)= R.H.S Thus Proved
We have not considered the time element in our decoding. An important time for decoding is the time from the address strobe (AS) to when the data is required in a read. Time
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A school district has I neighbourhoods, J schools and G grades at every school. Every school j has a capacity of C jg for grade g. In every neighbourhood i, the student population
what is spatial parallelis
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