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Prove the equations using the Boolean algebraic theorems that is given belowA‾BC + AB‾C + ABC‾+ ABC = AB + BC + ACAns. The equation given is A‾BC + AB‾C + ABC‾+ ABC = AB + BC + ACL.H.S = A‾BC + AB‾C + ABC‾+ ABC= A‾BC + AB‾C + AB (C +C‾)= A‾BC + AB‾C + AB (Q C + C‾ = 1)= A‾BC + A (B + B‾C)= A‾BC + A (B + C) (? B + B‾C = B + C)= A‾BC + A B + AC= C (A + A‾B) + AB + AC= C (A + B) + A B + AC (? A + A‾B = A + B)= AC + BC + AB + AC= AB + BC + AC (? AC + AC = AC)= R.H.S Thus Proved
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mod12 counter connection diagram
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