Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
The next thing that we must acknowledge is that all of the properties for exponents. This includes the more general rational exponent that we haven't looked at yet.
Now the properties of integer explore are valid for this section also then we can see how to deal with the more general rational exponent. In fact there are two different ways of dealing along with them as we'll see. Both of the methods involve via property 2 from the previous section. For reference reason this property is,
(an )m = anm
Thus, let's see how to deal along with a general rational exponent. First we will rewrite the exponent as follows.
b m /n = b(1/n) (m)
In other terms we can think of the exponent like a product of two numbers. We will now use the exponent property illustrated above. Though, we will be using it in the opposite direction than what we did in the earlier section. Also, there are two ways to do it. Here they are following,
b m /n = ( b 1/n ) Or b m/ n =(bm )1/n
By using either of these forms now we can evaluate some more complicated expressions
Definition of Natural exponential function: The natural exponential function is f( x ) = e x where, e= 2.71828182845905........ . Hence, since e > 1 we also know that e x
word problem
Find the largest possible positive integer that will divide 398, 436, and 542 leaving remainder 7, 11, 15 respectively. (Ans: 17) Ans: The required number is the HCF of the n
4 accounting majors, 2 economics majors and 3 marketing majors have an interview for5 different positions with a large company. Find the number of dfferent ways that 5 of these c
jobs a b c d e f 1 15 8 6 14 6 26 2 17 7 9 10 15 22 3 21 7 12 9 11 19 4 18 6 11 12 14 17
Rule 1 The logarithm of 1 to any base is 0. Proof We know that any number raised to zero equals 1. That is, a 0 = 1, where "a" takes any value. Therefore, the loga
Suppose S = {vi} and T = {ti} are "easy" sets of knapsak weight. Also, P and q are primes p > ?Si and q > ?ti. We can combine S and T into a signle set of knapsack weight as follow
A 3 km pipe starts from point A end at point B Population = 3000 people Q = 300 L/day/person Roughness = cast ion pipe Length of the pipe = 3km Case 1 From A to B
jenna asked 100 of her schoolmates if they have had their first kiss and 43 of them said yes
I need help converting my project fractions to the number 1.
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +1-415-670-9521
Phone: +1-415-670-9521
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd