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Proof of Limit Comparison Test
As 0 < c <∞ we can find out two positive and finite numbers, m and M, like m < c < M .
Now, as
we know that for large enough n the quotient an/bn should be close to c and thus there must be a positive integer N like if n > N we as well have,
m < an / bn < M
Multiplying by bn provides
Mbn < an < Mbn
provided n > N .
Here now, if ∑bn diverges then thus does ∑mbn and so as mbn < an for all adequately large n by the Comparison Test ∑an as well diverges.
Similarly, if ∑bn converges then so does ∑Mbn and as an < Mbn for all sufficiently large n by the Comparison Test ∑an as converges.
I would like to calculate the high point of a mathematical formula with two unknown variables. At the same time I made the 1st derivation of the function. How can I best program th
Evaluate the log function: Calculate 3log 10 2. Solution: Rule 3. log (A n ) = nlog b A 3log 10 2 = log 10 (2 3 ) = log 10 8 = 0.903
a couple q''s
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if theta is a positive acute angle and 2sin theta +15cos square theta=7 then find the value of cot theta
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Solve by factorization X 2 +(a/a+b + a+b/a)x+1 = 0 X 2 +(a/a+b + a+b/a)x+1 => X 2 +(a/a+b x a+b/ax + a/a+b .a+b/a) => X[x+a/a+b] +a+b/a[a+a*a+b]= 0 => X= -a
solutions for the equation a-b=5
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