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Proof of Limit Comparison Test
As 0 < c <∞ we can find out two positive and finite numbers, m and M, like m < c < M .
Now, as
we know that for large enough n the quotient an/bn should be close to c and thus there must be a positive integer N like if n > N we as well have,
m < an / bn < M
Multiplying by bn provides
Mbn < an < Mbn
provided n > N .
Here now, if ∑bn diverges then thus does ∑mbn and so as mbn < an for all adequately large n by the Comparison Test ∑an as well diverges.
Similarly, if ∑bn converges then so does ∑Mbn and as an < Mbn for all sufficiently large n by the Comparison Test ∑an as converges.
Noah is renewing a magazine subscription. one package offers to renew the magazine for 3 years for 26$. A second package offers to renew the magazine for 5 years for $38
y''''+6y''+10y=10x^(4)+24x^(3)+2x^(2)-12x+18
The functions {sinmx; cosmx}; m = 0,....∞ form a complete set over the interval x ∈ [ -Π, Π]. That is, any function f(x) can be expressed as a linear superposition of these
Optimization : In this section we will learn optimization problems. In optimization problems we will see for the largest value or the smallest value which a function can take.
Explain the Graphical Technique of Linear Equations by using this figure.
tell me about the software of compound intrest?
solve for x: logx9
How can I submit a sample of my work in either teaching online or checking homework as I am retired and doing this for the first time?
#question.
Kelli calls her grandmother every month. Every other month,Kelli also calls her cousin in January, how many calls will Kelli have made to her grandmother and her cousin by the end
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