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A particle is projected from ground with velocity 40sqrt2m/s.find- a)velocity and b)displacement of particle after 2sec .Take g=10m/s^2 Ans)velocityv=u+ata=-gv=40√2-10*2v=20(2√2-1)m/ss=ut+at2/2s=40√2*2-10*2*2s=80√2-40s=40(2√2-1)m
Magnetism - Basic concepts: 1. Pole strength: The ability of a pole of a magnet to attract or repel another magnetic pole is called its pole strength. Units : A-m 2.
Write a mathematical expression for refractive index of the material of a prism in terms of its angle. Is the mathematical expression true for all positions of the prism?
What is the work done to take a particle of mass m from surface of the earth to a height equal to 2R (R=radius of earth )? Ans) Initial PE= - GMm/R Final PE = - GMm/3R
Q. A truck loaded with sand accelerates along a highway. If the driving force stays the same on the truck, what happens to the truck's acceleration if its trailer leaks sand at a
a magnatic train
How is laser in treatment use as cooling? Lasers cooling treatment: A technique which has had recent success is laser cooling. It involves atom trapping, a process where a n
The discharge over a triangular notch can be written as Q = (8/15) Cd (2g)0.5 tan(θ/2) H5/2 If an error of 1% in measuring H is introduced determine the corresponding error
can you please give me a step wise answer for finding the dimension of impulse
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Yes it is possible at the centre of the earth where the radius is zero .
given velocity v=40 root 2v=u+at where a=g1.v=u+at====>we have to get the value by using this formula2.s=ut+1/2gt^2 by using this formula wehave to get the value of displacements
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