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The goal of this question is to create a program that takes as input two images that are related by a homography, and which "warps" the second image (piscine2.bmp) to align with the first image (piscine1.bmp). Both of these images are on the course web site. The output image that is created should have the original first image, along with the warped version of the second image. I have made the first image big enough to hold both the original first image along with the warped version of the second image. Your program needs to find some features in the two images, match these features to compute a homography, and use this homography to help create the final image which is a combination of the two input images. The simplest way to accomplish this is to use the code from the program findmatch.cpp in the C Samples directory (which you can find in the Windows OpenCV program menu) and modify it as necessary. Send me your source code and the final output image that you create which combines the two input images. In the area of overlap between the two images we have a choice of using pixels from the first image, or the second image. Describe some reasonable strategy for using pixels from both images to create a perceptually pleasing blend (you do not have to implement this strategy, just give a short description).
What are the exceptions encountered for FP operation? The exceptions encountered for FP operation are overflow, underflow. /0, inexact and invalid values.
What is system testing? The final step in testing is system testing, which means checking the whole application. System testing exercises the overall application and make sure
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Generally the register storage is faster than cache andmain memory. Also register addressing uses much shorter addresses than addresses for cache and main memory. Though the number
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How many address bits are required to represent 4K memory ? Ans. 12 address bits are required for representing 4K memory, as 4K = 2 2 x 2 10 = 2 12 Therefore 1K = 1024
The decimal equivalent of (1100) 2 is ? Ans. (1100) 2 = (12) 10
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