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Program : Write a program to perform a one byte BCD addition.
Solution :
It is consider that the operands are in BCD form, but the CPU considers it as hexadecimal and accordingly performs addition operation. Assume the following example for addition. Carry is set to be 0.
Actual result after addition considering hex operand
In this program, the DAA instruction is used after ADD. In similar manner, DAS can be used after instruction SUB.
IInd Generation Microprocessor : The second generation microprocessor by using n MOS technology seemed in the market in 1973. The Intel 8080, of nMOS technology
Typical link to modems for synchronous and asynchronous transmissions are shown in Figure. With regard to the synchronous connections it is consider that the timing is controlled
Trying to convert small programs from C to 8086 assembly language using emu 8086 emulator. I converted to low level C, but struggling with converting to the Assembly language.
Comparison between 8086 and 8088 All the changes in 8088 above 8086 are indirectly or directly related to the 8-bit, 8085 compatible data and control bus interface. 1) The p
take an integer and its base and the base in which you want to convert the number from user and perform conversion.
Program: Write a program to perform addition of a series of 8-bit numbers. The series have 100 (numbers). Solution : In the first program, we have been implemented the add
ASSUME: Assume Logical Segment Name:- The ASSUME directive which is used to inform the assembler, the specified names of the logical segments to be consider for different segme
INTO : Interrupt on Overflow:- It is executed, when the overflow flag OF is set. The new contents of IP and CS register are taken from the address 0000:0000 as described in INT
SHORT : The SHORT operator denoted to the assembler that only one byte is needed to code the displacement for a jump (for example displacement is within -128 to +127 bytes fr
Ask 2. Exchange higher byte of AX and higher byte of BX registers by using memory location 0160 in between the transfer. Then stores AX and BX registers onto memory location 0174 o
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