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Program : A program to move a string of the data words from offset 2000H to offset 3000H the length of the string is OFH.
Solution :
For writing this program, we will use an significant facility, available in the 8086 instruction set, for example move string byte/word instruction. We will also study the flexibility imparted by this instructions to the 8086 assembly language program. First write the Program for 8085, supposing that the string is available at location 2000H and is to be moved at 3000 H.
Now consider DS is suitably set, write the sequence for 8086. At first by using the index registers, the program may be written as given.
BY Comparing the above listings for 8085 and 8086 we can conclude that every instruction in 8085 listing is replaced by an alike instruction of 8086. The above 8086 listing is completely correct but it is not competent. Let us try to write the listings for the similar purpose by using the string instruction. Due to the assembler directives and the syntax, one may sense that the program is lengthy, though it eliminates 4 instructions for a MOVSW instruction.
MOVSW/MOVSB : Move String Word or String Byte: Imagine a string of bytes, stored in a set of consecutive memory locations is to be moved to another set of the destination locati
External Hardware-Interrupts External hardware-interrupts are generated by controllers of external devices or coprocessors and are connected to the processor pin for Non Mask a
1. Write an assembly program that adds the elements in the odd indices of the following array. Use LOOP. What is the final value in the register? array1 DWORD 10, 20, 30, 40, 50, 6
program on basic calculator
64-bit integer calculator, which processes using 16-bits at a time (reg/mem16 operands)
to find the matrix addition
SHR : Shift Logical Right: This instruction performs bit-wise right shifts on the operand word or byte that might be reside in a memory location or a register, by the specified c
DEC: Decrement :- The decrement instruction subtracts 1 from the contents of the particular memory location or register. All the conditions code flags except carry flag are affec
Example : Add the contents of the 2000H: 0500H memory location to contents of 3000H: 0600H and store the result in 5000H: 0700H. Solution : Unlike the past example progra
RCR: Rotate Right through Carry:- This instruction rotates the contents bit-wise of the destination operand right by the specified count through carry flag (CF). For each operati
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