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Write a MC68H12 assembly language program to find the largest number in an array of ten 8-bit numbers. The array is stored in memory locations starting at address $1100. Use branch instructions and loops.
Write and test your programs using Freescale CodeWarrior (you may use another assembler if you so wish). You should also turn in a printed report that contains the following:
1. Your programs, accompanied by proper documentation (comments)
2. Initial, intermediate and final snapshots of the CodeWarrior status window (the window that shows the values of registers) and the CodeWarrior memory window, for each part of this homework, A, B, and C.
1. Write an assembly program that adds the elements in the odd indices of the following array. Use LOOP. What is the final value in the register? array1 DWORD 10, 20, 30, 40, 50, 6
Multiply two numbers by using shift and rotate instruction
I need a division subroutine. Asks for two inputs, then displays the inputs and shows the answer with a remainder. Mine isnt displaying the inputs correctly.
from pin description it seems that 8086 has 16 address/data lines i.e.AD0_AD15.The physical address is however is larger than 2^16.How this condition can be handled
00h-1h
Write a program that allows a user to encrypt/decrypt a message using a shift cipher. The user should specify the key and the message. Your program should be able to handle messa
Physical Memory Mapped I/O and Port I/O : CPU controlled I/O comes in 2 ways. Simply the difference is whether we utilize the normal memory addresses for I/O, this is mention
.MODEL SMALL .STACK 100H .DATA PROMPT DB \''The 256 ASCII Characters are : $\'' .CODE MAIN PROC MOV AX, @DATA ; initialize DS MOV DS, AX
IMUL: Signed Multiplication: This instruction multiplies a signed byte by a signed bit in source operand e in the register AL or signed word in source operand by signed word in th
Program : A program to move a string of the data words from offset 2000H to offset 3000H the length of the string is OFH. Solution : For writing this program, we will use
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