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THIS PROGRAM IS TO DISPLAY A STOCK CONTAINING ITEM CODE,ITEM NAME,PRICE AND ANOTHER STOCK WITH CODE & QUANTITY AND DISPLAY COMPLETE INFORMATION#include #include #include struct stock { int itemcode; char itemname[30]; float unitprice; };struct stock1 { int itemcode; int quantity; };void main() { clrscr(); stock s[50]; stock1 s1; float amt; int number; cout<<"enter the no. of items to be purchased : "; cin>>number; cout< for(int i=0;i { cout<<" Item code : "; cin>>s[i].itemcode; cout<<" Item name : "; gets(s[i].itemname); cout<<" Unit price of the item : "; cin>>s[i].unitprice; cout< } cout<<"enter the item code of the item to be purchased : "; cin>>s1.itemcode; cout<<"enter the total quantity : "; cin>>s1.quantity; cout< for(i=0;i { if (s[i].itemcode == s1.itemcode) { amt = s[i].unitprice * s1.quantity; clrscr(); cout<<"\t B I L L "<<"\n\n"; cout<<" item code : "< cout<<" item name : "< cout<<" unit price : "< cout<<" quantity : "< cout<<"\n"; cout<<" total amount : "< } else { clrscr(); cout<<" THE ITEM IS NOT AVAILABLE "; } } getch(); }
Implementation of the Dictionary class: int Dictionary::find_word(char *s) { char word[81]; for (int i = 0; i if (stricmp(words[i].get_word(word),s) =
i want to check the command line argument is whether an integer or a string
My project is compiling but the equation entered is not working
#include stdio.h> #include conio.h> #include string.h> void main() { char a[50],b[25][25],l[25],temp1; int i=0,j=0,k=0,l1[25],c=0,c1=0,t=
write an algorithm for linear search algorithm
In this worksheet you are asked to write three classes in C++: Lecture class, Course class and University class. The classes relate to each other in the way that a Course has many
program for lexicographically precedes the given input permutation
How do you know that your class requires a virtual destructor? A: If at least your class has one virtual function, you must make a destructor for this class virtual. It will let
Define the Keywords of c language? C keeps a small set of keywords for its personal use. These keywords can't be used as identifiers in the program. Here is the list of keyword
F u nction Returning Object: This program is like to the previous program except the function returns object. The main rule to be remembered is the function returning obj
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