Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Convert compass heading in degrees (0-360 degrees)to compass bearing. A compass bearing consist of three items namely:
a.The direction you face (North or South)b.An angle between 0 to 90 degrees.c.The direction you turn before walking (East or West).
For example,to get the compass bearing for a compass heading of 110 degrees,you would first face due south(180 degrees)and then turn 70 degrees East.Therefore,the compass bearing is South 70 degrees East.Create a C program that will accept a compass heading and display the equivalent compass bearing./* Directives */ #include int main(void){ double heading; /*compass heading in degrees*/ /* Get compass heading */ do{printf("Enter a Compass Heading: ");scanf("%lf", &heading); /* Display equivalent compass bearing */ if (heading < 0.0 || heading > 360.0)printf("Please Input a Compass Heading between 0 and 360 Degrees.\n", heading);} while (heading < 0.0 || heading > 360.0); if(heading <= 90.0) printf("Compass Bearing: North %.1f Deg East\n", heading); else if(heading < 180.0) printf("Compass Bearing: South %.1f Deg East\n", 180 - heading); else if(heading <= 270.0) printf("Compass Bearing: South %.1f Deg West\n", heading - 180.0); else if(heading <360.0) printf("Compass Bearing: North %.1f Deg West\n", 360.0 - heading); else if(heading == 360.0) printf("Compass Bearing: North %.1f Deg East\n", 360.0 - heading);else printf("Please Input a Compass Heading between 0 and 360 Degrees.\n", heading); /* End Program */return(0);}
Q-What is your reaction to following line of code? delete this; A: This is not a good programming Practice. A good programmer will insist that you must absolute
Define a procedure that takes three numbers as arguments and returns the sum of the squares of the two larger numbers.
In general, Roman numerals can be converted mathematically by simply assigning a numerical value to each letter, according to the chart below, and calculating a total: M=1000 | D=5
char P[100]; double X=533.8*22500; sprintf(P,"%f %u",X,(unsigned int)X); MessageBox(P,"SSS"); //12010500.000 12010499
write a program that counts the number of occurrences of the string in the n-th padovan string p(n) program 1 : package test.padovanstring; public class PadovanString {
Write a algorithm to explain the processof wakingbup in morning
At a shop of marbles, packs of marbles are prepared. Packets are named A, B, C, D, E …….. All packets are kept in a VERTICAL SHELF in random order. Any numbers
Program is to perform string operations: Program is to perform string operation without using in built functions using classes and object void mainmenu() { clrs
A Padovan string P(n) for a natural number n is defined as: P(0) = ‘X’ P(1) = ‘Y’ P(2) = ‘Z’ P(n) = P(n-2) + P(n-3), n>2 where + denotes string concatenation. For a string of the c
Program to calculate tax: float tax (float) ; int main() { float purchase, tax_amt, total; cout cin >> purchase
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd