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THIS PROGRAM IS TO COMPARE THE TWO DATES GIVEN BY THE USER#include #include #include struct date { int dd; int mm; int yy; };date compare(date d1,date d2) { if (d1.dd { cout<<" 2nd date day is bigger "; } else if(d2.dd { cout<<" 1nd date day is bigger "; } else if(d1.dd==d2.dd) { cout<<" "; } if (d1.mm { cout<<" 2nd month is bigger "; } else { cout<<" 1nd month day is bigger "; } if(d1.yy>d2.yy) { cout<<" 1st date is bigger " ; } else if (d1.dd==d2.dd && d1.mm==d2.mm && d1.yy==d2.yy ); { cout<<" the dates are equal "; } if(d2.yy>d1.yy) { cout<<" 2nd date is bigger "; } }void main() { clrscr(); date d1,d2,ans; cout<<" enter the 1st date (dd/mm/yyyy) "; cin>>d1.dd; cin>>d1.mm; cin>>d1.yy; cout<<" enter the 2nd date (dd/mm/yyyy) "; cin>>d2.dd; cin>>d2.mm; cin>>d2.yy; compare(d1,d2); }
Can you think of a condition where your program would crash without attaining the breakpoint that you set at the starting of main()? A: C++ let for dynamic initialization of glo
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Primarily the term alignment refers the tendency of an address pointer value to be a multiple of some power of two. Thus a pointer with two byte alignment contains a zero in the le
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Blanche has a fashion design company called BLB_Best_Clothing Pty. That she has just opened recently
C Program to FIND THE EVEN WORDS IN THE STRING #include conio.h> #include stdio.h> void main() { char a[50],temp; int i=0,k=0,l[25],c=0,r=0;
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Public derivation Public derivations are much more common than private derivations. In this situation: The private members inherited from the base class are inaccessible
Draw pie chart in c++ program: int main() { char cmd; cout cout cmd = toupper(getch());
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