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#include using namespace std; void print(int marks_arr[],int cnt) { int ind[cnt]; int i=0; int j=0; int k=0; int s=0; for(k=0;k {ind[k]=0; } int cnt1=0; for(i=0;i { ind[cnt1]=1; for(j=i+1;j { //cout< if((marks_arr[i]==marks_arr[j])&&(marks_arr[i]!=-1)) { ind[cnt1]=ind[cnt1]+1; marks_arr[j]=-1; //if(marks_arr[j]==-1) //{ //break; //}
} } cnt1++; } for(s=0;s { if(marks_arr[s]!=-1) { cout<<"\n"< }
}
} int add() { int mark; cout<<"Enter the mark:"; cin>> mark; return mark; } float avg(int mark[],int c) { int i,sum=0; float average; for(i=0;i { sum= sum+mark[i]; } average=sum/c; return average; } int marks_arr[100]; int main() { static int count=0; //int marks_arr[100], int choice,i,ch,searchelement,totalcount,total; float val; do { cout<<"\n 1. Add student marks"; cout<<"\n 2. Display student marks"; cout<<"\n 3. Find average of all marks"; cout<<"\n 4. Calculate the standard deviation"; cout<<"\n 5. Delete a student mark"; cout<<"\n 6. Search all marks "; cout<<"\n 7. Print all marks";cout<<"\nEnter choice : "; cin>>choice; switch(choice) { case 1: { marks_arr[count]=add(); count++; break; } case 2: { for(i=0;i { cout< } break; } case 3: { val= avg(marks_arr,count); cout<< "The avg of total marks is: "< break; } case 4: case 5: case 6: { cout<<"\n Enter the mark to search:"; cin>>searchelement; totalcount=0; for(i=0;i { if(marks_arr[i]==searchelement) { totalcount=totalcount+1; } } cout<<"No of times the element is present : "< break; }case 7: { print(marks_arr,count); } } cout<<"\nContinue [0-yes / 1-no] :"; cin>>ch; }while(ch!=1); }
Increment and Decrement Operators. The operator for increment is '++' and decrement is '-'. These operators enhances or decrease the value of a variable on which they are ope
Q: however shouldn't I always use a printOn() method instead of a friend function? A: No. The usual cause people wish to always use a printOn() method instead of a friend fu
I Want a answer for solving the big M method in the topic of simplex method...
want the codings for these topic in ur experts minds.com
A: This will turn o_ "name mangling" for func so that one can connect to code compiled by a C compiler.
Write a function to accept a character and display it 40 times.
(a) Pairs may be represented using a lambda. Using only lambdas, create a procedure (triple x y z) that constructs a triplet. You may NOT use car, cons or cdr in the triplet proced
Implement a multithreaded server that can be used as a proxy server to access some designated file (say it reflects the proxy copy of two file1.txt, file2.txt). Now use a client to
Converting Base Type to Class Type (char to string) class String { char *name; int length; public: String(void) {length =0; name = new char[length+1];
source code
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