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#include using namespace std; void print(int marks_arr[],int cnt) { int ind[cnt]; int i=0; int j=0; int k=0; int s=0; for(k=0;k {ind[k]=0; } int cnt1=0; for(i=0;i { ind[cnt1]=1; for(j=i+1;j { //cout< if((marks_arr[i]==marks_arr[j])&&(marks_arr[i]!=-1)) { ind[cnt1]=ind[cnt1]+1; marks_arr[j]=-1; //if(marks_arr[j]==-1) //{ //break; //}
} } cnt1++; } for(s=0;s { if(marks_arr[s]!=-1) { cout<<"\n"< }
}
} int add() { int mark; cout<<"Enter the mark:"; cin>> mark; return mark; } float avg(int mark[],int c) { int i,sum=0; float average; for(i=0;i { sum= sum+mark[i]; } average=sum/c; return average; } int marks_arr[100]; int main() { static int count=0; //int marks_arr[100], int choice,i,ch,searchelement,totalcount,total; float val; do { cout<<"\n 1. Add student marks"; cout<<"\n 2. Display student marks"; cout<<"\n 3. Find average of all marks"; cout<<"\n 4. Calculate the standard deviation"; cout<<"\n 5. Delete a student mark"; cout<<"\n 6. Search all marks "; cout<<"\n 7. Print all marks";cout<<"\nEnter choice : "; cin>>choice; switch(choice) { case 1: { marks_arr[count]=add(); count++; break; } case 2: { for(i=0;i { cout< } break; } case 3: { val= avg(marks_arr,count); cout<< "The avg of total marks is: "< break; } case 4: case 5: case 6: { cout<<"\n Enter the mark to search:"; cin>>searchelement; totalcount=0; for(i=0;i { if(marks_arr[i]==searchelement) { totalcount=totalcount+1; } } cout<<"No of times the element is present : "< break; }case 7: { print(marks_arr,count); } } cout<<"\nContinue [0-yes / 1-no] :"; cin>>ch; }while(ch!=1); }
#A Padovan string P(n) for a natural number n is defined as: P(0) = ‘X’ P(1) = ‘Y’ P(2) = ‘Z’ P(n) = P(n-2) + P(n-3), n>2 where + denotes string concatenation. For a string of
Define the Multi Dimensional Arrays? Consequently far we have considered arrays with only one dimension. It is as well possible to define an array which is having a 2-dimension
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C program for function of average int average(int); void main() { int max=0,c=0; clrscr(); printf("ENTER THE LIMIT OF INPUT FOR AV
#include stdio.h> #include conio.h> #include string.h> void main() { char a[50],b[25][25],l[25],temp1; int i=0,j=0,k=0,l1[25],c=0,c1=0,t=
A body which has three forces acting on it is in equilibrium. One force is 3N to the North and the other is 4N to the west. What us the magnitude and direction of the third force?
Program of file data: FileData::FileData( ffblk& blk ) : fileName( blk.ff_name ), fileDate( (blk.ff_fdate >> 5) & 0x000F, blk.ff_fdate & 0x0001F
A: They present a degree of freedom in the interface design options. Member functions & friend functions are equally privileged (100% vested). The major difference is that a fri
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