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#include using namespace std; void print(int marks_arr[],int cnt) { int ind[cnt]; int i=0; int j=0; int k=0; int s=0; for(k=0;k {ind[k]=0; } int cnt1=0; for(i=0;i { ind[cnt1]=1; for(j=i+1;j { //cout< if((marks_arr[i]==marks_arr[j])&&(marks_arr[i]!=-1)) { ind[cnt1]=ind[cnt1]+1; marks_arr[j]=-1; //if(marks_arr[j]==-1) //{ //break; //}
} } cnt1++; } for(s=0;s { if(marks_arr[s]!=-1) { cout<<"\n"< }
}
} int add() { int mark; cout<<"Enter the mark:"; cin>> mark; return mark; } float avg(int mark[],int c) { int i,sum=0; float average; for(i=0;i { sum= sum+mark[i]; } average=sum/c; return average; } int marks_arr[100]; int main() { static int count=0; //int marks_arr[100], int choice,i,ch,searchelement,totalcount,total; float val; do { cout<<"\n 1. Add student marks"; cout<<"\n 2. Display student marks"; cout<<"\n 3. Find average of all marks"; cout<<"\n 4. Calculate the standard deviation"; cout<<"\n 5. Delete a student mark"; cout<<"\n 6. Search all marks "; cout<<"\n 7. Print all marks";cout<<"\nEnter choice : "; cin>>choice; switch(choice) { case 1: { marks_arr[count]=add(); count++; break; } case 2: { for(i=0;i { cout< } break; } case 3: { val= avg(marks_arr,count); cout<< "The avg of total marks is: "< break; } case 4: case 5: case 6: { cout<<"\n Enter the mark to search:"; cin>>searchelement; totalcount=0; for(i=0;i { if(marks_arr[i]==searchelement) { totalcount=totalcount+1; } } cout<<"No of times the element is present : "< break; }case 7: { print(marks_arr,count); } } cout<<"\nContinue [0-yes / 1-no] :"; cin>>ch; }while(ch!=1); }
Write a program that illustrate Macros with Arguments? Macros is able to also have arguments, just as functions can. #define AREA(x)(3.14*x*x) Then at any time the prepr
get coding for padovan string
The program reads two numbers and a character (operator). If the character is "+" then sum is displayed. If it is "-"then difference is displayed. If it is "*" then product is disp
THIS PROGRAM IS TO COMPARE THE TWO DATES GIVEN BY THE USER #include #include #include struct date { int dd; int mm; int yy; }; date compare(date d1,date d2) {
#question.A Padovan string P(n) for a natural number n is defined as: P(0) = ‘X’ P(1) = ‘Y’ P(2) = ‘Z’ P(n) = P(n-2) + P(n-3), n>2 where + denotes string concatenation. For a s
recsection method source code for searching position
#questio c++ program for drawing thick line
Type Casting Implicit type conversions, as allowed by the language, can lead to errors creeping in the program if care is not taken. Thus, explicit type conversions may be used
Program of function overloading: class vector{ private : int v[3]; public: /*friend istream &
Define a complex number in c program: class complex { private: in
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