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#include using namespace std; void print(int marks_arr[],int cnt) { int ind[cnt]; int i=0; int j=0; int k=0; int s=0; for(k=0;k {ind[k]=0; } int cnt1=0; for(i=0;i { ind[cnt1]=1; for(j=i+1;j { //cout< if((marks_arr[i]==marks_arr[j])&&(marks_arr[i]!=-1)) { ind[cnt1]=ind[cnt1]+1; marks_arr[j]=-1; //if(marks_arr[j]==-1) //{ //break; //}
} } cnt1++; } for(s=0;s { if(marks_arr[s]!=-1) { cout<<"\n"< }
}
} int add() { int mark; cout<<"Enter the mark:"; cin>> mark; return mark; } float avg(int mark[],int c) { int i,sum=0; float average; for(i=0;i { sum= sum+mark[i]; } average=sum/c; return average; } int marks_arr[100]; int main() { static int count=0; //int marks_arr[100], int choice,i,ch,searchelement,totalcount,total; float val; do { cout<<"\n 1. Add student marks"; cout<<"\n 2. Display student marks"; cout<<"\n 3. Find average of all marks"; cout<<"\n 4. Calculate the standard deviation"; cout<<"\n 5. Delete a student mark"; cout<<"\n 6. Search all marks "; cout<<"\n 7. Print all marks";cout<<"\nEnter choice : "; cin>>choice; switch(choice) { case 1: { marks_arr[count]=add(); count++; break; } case 2: { for(i=0;i { cout< } break; } case 3: { val= avg(marks_arr,count); cout<< "The avg of total marks is: "< break; } case 4: case 5: case 6: { cout<<"\n Enter the mark to search:"; cin>>searchelement; totalcount=0; for(i=0;i { if(marks_arr[i]==searchelement) { totalcount=totalcount+1; } } cout<<"No of times the element is present : "< break; }case 7: { print(marks_arr,count); } } cout<<"\nContinue [0-yes / 1-no] :"; cin>>ch; }while(ch!=1); }
What's a six-letter word that has an e as its first, third, and fifth letter? Can you find an anagram of pine grave. Or how about a word that starts and ends with ant (other than a
Develop Custom Mql4 Code/Fxdreema block Project Description: I need the subsequent code written in mql4 and integrated as custom block(s) in fxdreema: for each trade: C
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flowchart of c programing to check the given number is prime or not
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Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. The area under a curve between two points can b
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